What is the greatest common factor of 8m, 36m", and 12?

Mathematics

1 answer:

wlad13 [49]3 years ago

4 0

Answer: 4

Step-by-step explanation:

8m = 2*2*2*m

36m^3 = 2*2*3*3*m*m*m

12 = 2*2*3

GCF=2*2

Hope this helps!!

You might be interested in

During its first year in business, Alice's restaurant shows a loss of $12,000. During its second year, the restaurant makes a pr

galina1969 [7]

Answer:

$10,000

Step-by-step explanation:

-12,000+23,200-1,200= 10,000

8 0

3 years ago

The sum of 4 consecutive multiples of 6 is 540. What is the greatest of these numbers?

pychu [463]

Answer:

144

Step-by-step explanation:

First: 6x

Second: 6x+6

Third: 6x+12

Fourth: 6x+18

- Since they're multiples of 6

$6x+6x+6+6x+12+6x+18=540$

$24x+36=540\\$

Subract 36 from each side give us...

$24x=504\\x=21$

$21(6)+18=144$

Hope this helped! Please mark brainliest :)

4 0

3 years ago

Find the quotient.

posledela

Answer :

$B. 16 {a}^{2}c$

step-by-step explanation :

$48 {a}^{3}b{c}^{2} \div 3abc$

This can be rewritten as:

$\frac{ 48 {a}^{3}b {c}^{2} }{3abc}$

Now,

$\frac{48}{3}=16$

The law of indices states that:

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$

It implies that, when dividing two expressions with the same bases, repeat one of the bases and subtract the exponents.

Therefore,

$\frac{ {a}^{3} }{a}= {a}^{3 - 1} = {a}^{2}$

$\frac{b}{b} = {b}^{1 - 1} = {b}^{0} = 1$

Note: Any non-zero number exponent zero is 1

Also

$\frac{ {c}^{2} }{c} = {c}^{2 - 1} = {c}^{1} = c$

Hence:

$\frac{ 48 {a}^{3}b {c}^{2} }{3abc} = 16 {a}^{2}c$