F(x,n,p)=C(n,x)p^x*(1-p)^(n-x)
n=9, p=0.8 =>
f(x,9,0.8)=C(9,x)0.8^x*(0.2)^(9-x)
The function f(x,9,0.8) is then calculated using the above formula
x f(x)
0 0.0000001 0.0000182 0.0002953 0.0027534 0.0165155 0.0660606 0.1761617 0.3019908 0.3019909 0.134218
Check Sum f(x), [x=0,9] = 1.0 ok
3m^2+2p^2-15
3(3)^2+2(10)^2-15
3(9)+2(100)-15
21+200-15
206
How are you? Ok so It probably B but I’m not sure so just wait a few minutes till someone else answers because I’m not sure
Answer:
18
Step-by-step explanation:
you can do 12/2 to get 6 (the scale factor) and then multiply 3 by 6 and get 18
Answer:
x=3.50
Step-by-step explanation:
2*3.50=7
7-1=6
3+6=9
9+11=20
