Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
THE ANSWER IS THE SECOND AND THIRD CHOICE.
4. 3(y + 4y) this is distributive property! Hope it helps. Btw can you please check out a question on my page? thanks!! <span />
Theres a saying: Dividing fractions dont ask why, just flip the second and multiply.
so a/b / c/d = a/b * d/c
-8/2 * -3/6
1. cross - cancel common factor 2
4/2 * -3/3
2. Multiply
-4(-3)/ 2*3
3. multiply numbers
--12/2*3
- -12/6
4. Apply fraction rule -a/b=- a/b
=-(-12/6)
5. divide
= -(-2)
6. Apply rule -(-a)=a
=2
Your answer would be 2
A plane has two dimensions and extends infinitely in both dimensions.