Answer:
t = 6 km/hour
And, J would be 4 km per hour
Step-by-step explanation:
Let us assume the speed of Tom be T
And, the Speed of Jim be J
Given that
T - J = 2 km /hr ...........(i)
After 3 hours distance between them = 30 km
As they are walking in the opposite direction
Thus,
Net speed =T + J
L ÷ (T+J) = 3
30 ÷ (T+J) = 3
T +J =10 ..............(2)
After solving these two equations
2T = 12
t = 6 km/hour
And, J would be 4 km per hour
Because of a linear pair then because of vertical angles and because all angles have to be 180 added up
You can answer this problem in two different ways: the first being (17 - 5) * x, and the second being 12 * x.
The answer is a because the original is 100% of their jump. Then you would add the extra 10% so it would equal 110%
Please thank me
Answer:
4 days
Step-by-step explanation:
We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.
P(x>3 cargo ships) = 1-P(x<=3)
P(x>3) = 1-P(x<=3)
P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]
![P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]](https://tex.z-dn.net/?f=P%28x%3E3%29%20%3D%201%20-%20%5B%5Cfrac%7Be%5E%7B-2%7D2%5E0%7D%7B01%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E1%7D%7B11%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E2%7D%7B21%7D%2B%5Cfrac%7Be%5E%7B-3%7D2%5E3%7D%7B31%7D%5D)
P(x>3) = 1- [0.1353(1+2+2+1.33)]
P(x>3) = 1-0.856
P(x>3) = 0.1431
Als n=30, expected number is
E(x) =30*P(x>3)
E(x) = 30*0.1431
E(x) = 4.293
I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships