Ask question

Ask question

All categories

3 years ago

15

In triangle ABC, the length of side AB is 13 inches and the length of side BC is 19 inches. Which of the following could be the

length of side AC?

1 answer:

damaskus [11]3 years ago

4 0

Answer:

19-13=6 there it is

Step-by-step explanation:

You might be interested in

Solve: 5h + 2(11 - h) = -5 *<br> h = -9<br> h = 9<br> h = -8<br> h = 8

BigorU [14]

Answer:

-9

Step-by-step explanation:

do distributive property first to eliminate the parenthesis.

5h + 22 - 2h = -5

combine like terms

3h + 22 = -5

move the 22 over by subtraction

3h = -27

divide

h = -9

6 0

3 years ago

Read 2 more answers

What are the first five terms of the pattern with the formula 2n + 2?

alukav5142 [94]

An = 2n + 2

a1 = 2(1) + 2 = 2 + 2 = 4
a2 = 2(2) + 2 = 4 + 2 = 6
a3 = 2(3) + 2 = 6 + 2 = 8
a4 = 2(4) + 2 = 8 + 2 = 10
a5 = 2(5) + 2 = 10 + 2 = 12

8 0

3 years ago

Scott sells tie-dyed T-shirts for $15 each.Each T-shirts cost him $5 to make.He also has $100 in fixed costs per year for his T-

sergeinik [125]

He has to sell 60 t-Shirts. if you need the work message me :D

3 0

4 years ago

Find the distance using the modulus of the difference between z1 = -8 + 3i and z2 = 7 - 4i. Show all work for full credit.

3241004551 [841]

Answer:

$\sqrt{274}$

Step-by-step explanation:

Given $z_1=-8+3i,\ z_2=7-4i.$

1. Find the difference $z_1-z_2:$

$z=z_1-z_2=-8+3i-(7-4i)=-8+3i-7+4i=(-8-7)+(3i+4i)=-15+7i.$

This complex number has real part $Rez=-15$ and imaginary part $Imz=7.$

2. The modulus of complex number z is

$|z|=\sqrt{Re^2z+Im^2z}=\sqrt{(-15)^2+7^2}=\sqrt{225+49}=\sqrt{274}.$

5 0

4 years ago

Read 2 more answers

The Sanchez Family pays $1,975 per month to rent a four-bedroom house. They are planning to buy a house and make monthly payment

yuradex [85]

Determine the additional cost of housing for a month.

$2590-1975=615$

Determine the additional cost of housing for a year.

$12\cdot615=7380$

The moving charge is 545

3 0

1 year ago