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Tresset [83]
3 years ago
9

Equation of the circle with center 2,1 and 5,2 a point on the circle

Mathematics
2 answers:
Rufina [12.5K]3 years ago
6 0

Answer:

Step-by-step explanation:

The center tells you how to handle the left side of a circle's equation.

(x - 2)^2 + (x - 1)^2 = r^2

The point (5,2) gives you enough information to find r^2

x = 5

y = 2

(5 - 2)^2 + (2 - 1)^2 = r^2

(3)^2 + 1^2 = r^2

9 + 1 = r^2

r^2 = 10

Complete equation

(x - 2)^2 + (y - 1)^2 = 10

olasank [31]3 years ago
3 0

Answer: (x-2)^2+(y-1)^2=10

Step-by-step explanation:

r=√(x-h)^2+(y-k)^2

r=√(5-2)^2+(2-1)^2

r=√3^2+1^2

r=√9+1

r=√10

X^2+y^2=r^2

(x-2)^2+(y-1)^2=(√10)^2

(x-2)^2+(y-1)^2=10

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