There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
<h3><u>
Solution:</u></h3>
Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Yes, the student's theory is correct, because the survey shows that the seventh graders spend more time playing games on the weekend than the eighth graders.
W=4L/9
A=LW, using W found above gives us
A=L(4L/9)
A=4L^2/9 and we were told that A=576 so
4L^2/9=576 multiply both sides by 9
4L^2=5184 divide both sides by 4
L^2=1296 take the square root of both sides
L=36, and we know that W=4L/9 so
W=4(36/9)=16
So the dimensions are: width=16in and length=36in
To convert from a percentage to a decimal, move the decimal twice to the left
11% = 0.11
200% = 2.00
20.07% = 0.2007
198.4% = 1.984
Hope this helps!
Answer:
C.
Step-by-step explanation:
f(3) is referring to 3 on the left side and it is beside 1 which is on the left so it's 1.
