The answer is x equals the square root of y+1/4
Answer:
Y' = 360ex+ 30e
Step-by-step explanation:
Y=e×6x×(6x+1) × 5
y'= d/dx (e×6x ×(6x+1)×5)
y'=d/dx(30ex ×(6x+1))
y'=d/dx(180ex^2 + 30ex)
y'=d/dx(180ex^2) + d/dx (30ex)
Calculate the derivative
y'=180e×2x +30e
y'=360ex+30e
Answer:
Length of the bold sector: 40.3ft
Area of the bold sector: 282.08
Step-by-step explanation:
Finding the sector length: Assuming that pi=3.14, the diameter is 87.92 ft. The ratio of the bold section to the whole circumference is 165 to 360. So you need to multiply the circumference by the ratio. (87.92 x 165)/360=40.3
Finding the sector area: Assuming that pi=3.14, the area of the circle is 615.44 sq. ft. The ratio of the sector area to the area of the whole circle is 165:360. (615.44 x 165)/360=282.08, rounded to the nearest 100th.
Answer:
......................................................
Step-by-step explanation:
Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B%5Cfrac%7B1%7D%7B7%7D%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B1%7D%CF%80%20%3D%202%CF%80)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.
I am joyous to assist you anytime.
