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3 years ago

A reindeer can run 96 miles in 3 hours at this rate how far can a reindeer run in 1hour explain

1 answer:

6 0

This is how you do it: you put mile 96 over 3 and if u wanna know how many it will run in 1 hour. You cross multiply so you multiply 96 times1 and you get 96 but now you have to divide it by 3. If you do that you'll get the answer which is 32. There are other ways to do it but I just think it's way easier this way

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Missy stands at a horizontal distance of 45 ft from the base of a building. the angle of elevation from missy to the top of the

natita [175]

Tan 48° = $\frac{height}{45}$
height = tan 48° x 45 = 49.98 ft

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3 years ago

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Larry has already read 60 pages out of a 400 page book. He wants to finish the book in the next 20 days. The equation 20x + 60 =

antiseptic1488 [7]

Answer:

days

Step-by-step explanation:

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What is the surface area of the solid that this net can form?

vovangra [49]

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5x8=40

25x5=125

8x25=200

5x25=125

8x25=200

add those numbers and you get 730 :)

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3 years ago

If tan x = .76 and cos x = .22, what is sin x?

andrezito [222]

If we have in mind that tanx = sinx / cosxso we can rightly say that sinx=tanx×cosx
If you place the data in the right places, the answer should be 0.1672
I hope this can help you greatly

3 0

3 years ago

Dependent and Independent Events

Inessa05 [86]

Answer:

Step-by-step explanation:

Hello!

If you consider the 6-sided dice to be balanced, then each result has the same probability of occurrence: P(1)=P(2)=P(3)=P(4)=P(5)=P(6)= $\frac{1}{6}$

And each time Tom rolls the dice is independent of the other times, this means that you can disregard all previous rolls and calculate the 10nth time as if it is the 1st one.

Be the event A: "Tom rolled the dice for the 10nth time and obtained a 6"

The probability of A occurring will be P(A)= 1/6

On the other hand, the complement of "A" will be $A^c$ : "Tom rolled the dice for the 10nth time and didn't obtain a 6"

This means he could obtain a 1 or a 2 or a 3 or a 4 or a 5

You can calculate the probability pf this event by adding the probability of obtaining each value P( $A^c$ )= P(1)+P(2)+P(3)+P(4)+P(5)= 1/6*5= 5/6

Or by subtracting the probability of A to the total probability of the sample space:

P( $A^c$ )= 1 - P(A)= 1 - 1/6= 5/6

I hope this helps!

5 0

3 years ago