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3 years ago

2(5v+6)-6(-9v+2) Find the sum or difference.

Mathematics

2 answers:

nirvana33 [79]3 years ago

7 0

Answer:

64v

Step-by-step explanation:

2(5v+6)-6(-9v+2)

Distribute the 2 to everything in the parentheses.

10v+12-6(-9v+2)

Distribute the -6 to everything in the parentheses.

10v+12+54v-12

Combine like terms

64v

dybincka [34]3 years ago

4 0

I think the answer might be 64v

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Consider the standard form equation 2x-Ry=30. What value of R causes the graph to have a y-intercept of 5?

DochEvi [55]

Answer:

R = 6

Step-by-step explanation:

Given the equation of the line is 2x - Ry = 30

We know that the equation of a line with a as x-intercept and b as y-intercept is $\frac{x}{a} +\frac{y}{b} =1$

Now convert the above given line to the standard form

Divide the line by 30 we get

$\frac{2x}{30}-\frac{Ry}{30} =\frac{30}{30}$

$\frac{x}{15} -\frac{y}{\frac{30}{R} } =1$

Here the y-intercept is 30/R

Given y-intercept = 5

$\frac{30}{R} =5$

R = 6

4 0

3 years ago

Expand the following:<br> a) x(x - 6)<br> b) x(4x + 1)<br> c) 2x(5x + 4)<br> d) 3x(5x - y)

puteri [66]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

HELP PLEASE!!!

ch4aika [34]

Answer:

The population of Bear in 2050 is 4750000

Step-by-step explanation:

A) The exponential growth equation for bear is as follows -

dN/dT = rmax * N

Where dN/dT = change in population

rmax is the maximum rate of change

N = Base population

B) Here the per capita rate of increase (r) will always be a positive value irrespective of the and hence we will assume this population to be growing exponentially.

C) dN/dT = rmax * N

D) dN / 5 = 2.5 * 380,000

dN = 5*2.5 * 380000

= 4750000

8 0

3 years ago

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N