Answer:
0.56 m/s
Explanation:
The speed of the head at the end of the interval in each case is the area under the acceleration curve. Then the difference in speeds is the difference in areas.
We can find the area geometrically, using formulas for the area of a triangle and of a trapezoid.
A = 1/2bh . . . . area of a triangle
A = 1/2(b1 +b2)h . . . . area of a trapezoid
If h(t) is the acceleration at time t for a helmeted head, the area under that curve will be (in units of mm/s) ...
Vh = 1/2(h(3)·3) +1/2(h(3) +h(4))·1 +1/2(h(4) +h(6))·2 +1/2(h(6))·1
Vh = 1/2(4h(3) +3h(4) +3h(6)) = 1/2(4·40 +3·40 +3·80) = 260 . . . mm/s
If b(t) is the acceleration for a bare head, the area under that curve in the same units is ...
Vb = 1/2(b(2)·2 +1/2(b(2) +b(4))·2 +1/2(b(4) +b(6))·2 +1/2(b(6)·1)
Vb = 1/2(4b(2) +4b(4) +3b(6)) = 1/2(4·120 +4·140 +3·200) = 820 . . . mm/s
Then the difference in speed between the bare head and the helmeted head is ... (0.820 -0.260) m/s = 0.560 m/s
Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.
<h3>What is electric force?</h3>
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.
Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.
To learn more about the electric force refer to the link;
brainly.com/question/1076352
The buoyant force of an object which is submerged in water or any fluid is equal to the weight of the fluid displaced by an object.
why? the buoyant force goes up, and the gravitational pull goes down. <span />
Answer:
A digital signal picks up noise, but is still reliable.
Explanation:
Answer:
1. It won't break
2. 0.5 squared meters
Explanation:
1. Pressure (P) is force (F) exerted over an area(A). Greater the force or smaller the area, the pressure will be greater. This is presented by an equation:
P = F / A
This metallic object can be placed on the table in 3 different positions, depending on which its side is pressed against the table. Since its dimensions are 3 • 6 • 8 m, surface areas of these sides are:
A1 = 3 • 6 = 18m^2
A2 = 3 • 8 = 24m^2
A3 = 6 • 8 = 48m^2
It is already stated that the smaller are, greater the pressure, so this object will exert the greatest pressure if it's placed on the table with its 18m^2 side. In this case, pressure will be:
P = 400N / 18m^2
P = 22.2 N/m^2 (N/m^2 is the same unit as Pascal)
So, the table can withstand 250 Pa of pressure, the object exerts only 22.2 Pa, which means that the glass table won't break.
2. Again, we need to know the equation that connects the force and the pressure, and that is:
P = F / A
In this case, we have both the force and the pressure, and we want to find the surface of the area. From the previous equation, area can be found as:
A = F / P
A = 20N / 40Pa (N/m^2)
A = 0.5 m^2
So, the answer is: this pressure is exerted on the area of half of squared metar.