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Svetradugi [14.3K]
3 years ago
12

A box experiencing a gravitational force of 600 N. is being pulled to the right with a force of 250 N. 825 N. frictional force a

cting on the box as it moves to the right what is the net force in the Y direction
Physics
1 answer:
lidiya [134]3 years ago
8 0

Answer:A

Explanation:

Explanation:

Given that,

Gravitational force = 600 N

Frictional force = 25 N

Pulled by the Force = 250 N

We know that,

The gravitational force in downward and normal force act in upward. the frictional force in left side and the box pulled by the force to the right side.

The balance equation is along y-axis

The box will not move in y-axis therefore, the net force in the y-axis will be zero.

Hence, The net force in the y-direction will be zero.

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Explanation:

It is given that,

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The wavelength of a wave is given by :

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\lambda=\dfrac{3\times 10^8}{100}

\lambda=3\times 10^6\ m

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KE = \frac{1}{2}m* v^{2}

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In this case, h is eight, and PE is the same as KE:
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3,287.4= 91 * 9.81 * h

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