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Svetradugi [14.3K]
3 years ago
12

A box experiencing a gravitational force of 600 N. is being pulled to the right with a force of 250 N. 825 N. frictional force a

cting on the box as it moves to the right what is the net force in the Y direction
Physics
1 answer:
lidiya [134]3 years ago
8 0

Answer:A

Explanation:

Explanation:

Given that,

Gravitational force = 600 N

Frictional force = 25 N

Pulled by the Force = 250 N

We know that,

The gravitational force in downward and normal force act in upward. the frictional force in left side and the box pulled by the force to the right side.

The balance equation is along y-axis

The box will not move in y-axis therefore, the net force in the y-axis will be zero.

Hence, The net force in the y-direction will be zero.

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saul85 [17]

10.67m/s²

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Explanation:

Given parameters:

Mass of the body = 3kg

velocity of the mass = 4m/s

radius of circle = 0.75m

Unknown:

centripetal acceleration = ?

centripetal force = ?

Solution:

The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:

   Centripetal acceleration  = \frac{v^{2} }{r}

   v is the velocity of the body

    r is the radius of the circle

  putting in the parameters:

   Centripetal acceleration = \frac{4^{2} }{0.75}

    Centripetal acceleration = 10.67m/s²

Centripetal force = m  \frac{v^{2} }{r}

          m is the mass

 Centripetal force = mass x centripetal acceleration

                              = 3 x 10.67

                              = 32N

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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3 years ago
With a diameter that's 11 times larger than Earth's, _______ is the largest planet.
katovenus [111]
With a diameter that's 11 times larger than Earth's, Jupiter is the largest planet

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irga5000 [103]

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Now the radial force required to keep an object of mass m, moving in circular motion around a radius R, is given by

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Notice we don't use the kinetic coefficient even though the bike is moving.  This is because when the tires meet the road they are momentarily stationary with the road surface.  Otherwise the bike is skidding.

Now set these equal, since friction is the only thing providing the ability to accelerate (turn) without skidding off the road in a line tangent to the curve:

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