Answer:
MS access objects help the user list , information and designed reports .
Explanation:
MS access objects are create a forms, data base, tables,queries, and modules. There are many objects are following:-Tables, Forms,Reports, Queries.
Table:- These are objects used into a define and store the data,tables are contain the columns and the store of different data.
Form:- Form is the object that designed by the data input and control application queries or tables, forms are used in viewing records.
Reports:- Reports are the designed to the printing and calculating data,reports are used because data in read to easy format.
Queries:- Queries are provides that data from one or more table,you can define the update ,delete, insert, select data.
Answer:
The correct answer to the following question will be "Data".
Explanation:
- Data would be any series of one or even more signs which are given significance by unique classification action. To become knowledge the data needs to be interpreted.
- Data is generally considered to be the "bridge" that connects the designer's machine part with the practical side.
Therefore, this will be the right answer.
Answer:
Import java.awt.*;
import java.util.*;
public class Sprhere
{// Instance Data private double surfaceA, volume, r, diameter; //Constructors public Sphere ()
{r = 0;diameter = 0; surfaceA = 0;volume = 0;}
public Sphere (double radius, double d, double SA, double v)
{this. r = radius; this. diameter = d; this. surfaceA = SA;this.volume = v;}
//--------------------------------------------------------------------// Accesors.//--------------------------------------------------------------------public double get Radius()
{return r;}
public double get Diameter()
{return diameter;}
public double get SurfaceA()
{return surfaceA;}
public double get Volume()
{return volume;}
//--------------------------------------------------------------------// Mutators.//--------------------------------------------------------------------
Answer:
Check the explanation
Explanation:
CPI means Clock cycle per Instruction
given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M
Execution time is given by following Formula.
Execution Time(CPU time) = CPI*Instruction Count * clock time = 
a)
for system A CPU time is 1.3 * 100, 000 600 106
= 216.67 micro sec.
b)
for system B CPU time is 
= 333.33 micro sec
c) Since the system B is slower than system A, So the system A executes the given program in less time
Hence take CPU execution time of system B as CPU time of System A.
therefore
216.67 micro = =
Instructions = 216.67*750/2.5
= 65001
hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A