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Zinaida [17]
3 years ago
8

Which elements of text can be changed using automatic formatting? Check all that apply.

Computers and Technology
1 answer:
SIZIF [17.4K]3 years ago
7 0
A) smart quote and B) the zoom percentage and E) the addition of special characters
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Omnvmjsjskskskajskskzksososjfnjcjckskqnd
yarga [219]

what is the meaning to this??

4 0
3 years ago
CHALLENGE ACTIVITY 7.3.1: Functions: Factoring out a unit-conversion calculation. Write a function so that the main() code below
77julia77 [94]

Answer:

See Explaination

Explanation:

#include <stdio.h>

MphAndMinutesToMiles()

{

double milesPerHour;

double minutesTraveled;

double hoursTraveled;

double milesTraveled;

scanf("%lf", &milesPerHour);

scanf("%lf", &minutesTraveled);

hoursTraveled = minutesTraveled / 60.0;

milesTraveled = hoursTraveled * milesPerHour;

printf("Miles: %lf\n", milesTraveled);

}

int main()

{

MphAndMinutesToMiles();

return 0;

}

4 0
3 years ago
Expalin the defference between the driver of a desktop and a laptop​
Pani-rosa [81]

Answer:

None, drivers are hardware specific, if both devices share the same hadware manufacurer they tend to have the same drivers.

A driver is a software component that lets the operating system and a device communicate with each other. So asking for a difference in drivers is as asking the difference in hardware in both devices, though one tends to be more intergrated they are all the same in low level functions

Also drivers might not even communicate directly with the device but send a request. thats why some drivers can be written directly into an operating system.

7 0
3 years ago
Transaction processing systems (TPSs) provide valuable input to management information systems, decision support systems, and kn
nadezda [96]

A transaction is a simple task carried out as part of corporate operations. Transaction processing systems (TPS) handle business transactions for the corporation, supporting overall enterprise operations.

A TPS creates papers pertaining to a non-inquiry transaction and records the transaction itself, together with all of its results, in the database.

Today, TPS are required for business operations in practically every firm. TPSs feed information into organizational databases; they also serve as the framework for management-oriented information systems. Source data automation frequently involves direct data entering. Electronic data interchange is being utilized by transaction processing systems more and more. These systems offer computer-to-computer communication without the need for repeated data entry by substituting paper documents with formatted transaction data sent over telecommunications networks.

Learn more about information here-

brainly.com/question/15709585

#SPJ4

5 0
1 year ago
Given two complex numbers, find the sum of the complex numbers using operator overloading.Write an operator overloading function
Inessa05 [86]

Answer:

I am writing the program in C++ programming language.  

#include<iostream>  // to use input output functions

using namespace std;   // to identify objects like cin cout

class ProblemSolution {  //class name

private:  

// private data members that only be accessed within ProblemSolution class

int real, imag;

 // private variables for real and imaginary part of complex numbers

public:  

// constructor ProblemSolution() to initialize values of real and imaginary numbers to 0. r is for real part and i for imaginary part of complex number

ProblemSolution(int r = 0, int i =0) {  

real = r; imag = i; }  

/* print() method that displays real and imaginary part in output of the sum of complex numbers */

void print(){  

//prints real and imaginary part of complex number with a space between //them

cout<<real<<" "<<imag;}  

// computes the sum of complex numbers using operator overloading

ProblemSolution operator + (ProblemSolution const &P){  //pass by ref

          ProblemSolution sum;  // object of ProblemSolution

          sum.real = real + P.real;  // adds the real part of the  complex nos.

          sum.imag = imag + P.imag;  //adds imaginary parts of  complex nos.

//returns the resulting object

          return sum;       }  //returns the sum of complex numbers

};   //end of the class ProblemSolution

int main(){    //start of the main() function body

int real,imag;  //declare variables for real and imaginary part of complex nos

//reads values of real and imaginary part of first input complex no.1

cin>>real>>imag;  

//creates object problemSolution1 for first complex number

ProblemSolution problemSolution1(real, imag);  //creates object

//reads values of real and imaginary part of first input complex no.2

cin>>real>>imag;

//creates object problemSolution2 for second complex number

ProblemSolution problemSolution2(real,imag);

//creates object problemSolution2 to store the addition of two complex nos.

ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;

problemSolution3.print();} //calls print() method to display the result of the //sum with real and imaginary part of the sum displayed with a space

Explanation:

The program is well explained in the comments mentioned with each statement of the program. The program has a class named ProblemSolution which has two data members real and imag to hold the values for the real and imaginary parts of the complex number. A default constructor ProblemSolution() which initializes an the objects for complex numbers 1 and 2 automatically when they are created.

ProblemSolution operator + (ProblemSolution const &P) is the operator overloading function. This performs the overloading of a binary operator + operating on two operands. This is used here to add two complex numbers.  In order to use a binary operator one of the operands should be passed as argument to the operator function. Here one argument const &P is passed. This is call by reference. Object sum is created to add the two complex numbers with real and imaginary parts and then the resulting object which is the sum of these two complex numbers is returned.  

In the main() method, three objects of type ProblemSolution are created and user is prompted to enter real and imaginary parts for two complex numbers. These are stored in objects problemSolution1 and problemSolution2.  Then statement ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;  creates another object problemSolution3 to hold the result of the addition. When this statement is executed it invokes the operator function ProblemSolution operator + (ProblemSolution const &P). This function returns the resultant complex number (object) to main() function and print() function is called which is used to display the output of the addition.

4 0
4 years ago
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