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Arturiano [62]
4 years ago
14

Can somebody help me with this and explain the procedures?

Mathematics
2 answers:
IceJOKER [234]4 years ago
6 0

Answer:

Area of sector = 2.355 miles²

Step-by-step explanation:

Formula:

Area of circle = πr²

Where r is the radius

Area of sector = πr²(C/360)

Where C is the angle of sector

It is given that radius of circle is 6 miles

<u>To find the are of circle</u>

Here diameter = 6 miles,

radius r = diameter/2 = 3 miles

Area = πr² = 3.14 * 3² = 28.26 miles²

<u>To find area of sector</u>

Here r = 3 and C = 30°

Area of sector = πr²(C/360) = 28.26*(30/360)

= 2.355 miles²

levacccp [35]4 years ago
5 0

Answer: 2.35 square miles.

Step-by-step explanation:

To solve this exercise you must apply the formula for calculte the area of a sector in a circle, which is shown below:

A=r^2\pi(\frac{C}{360})

Where C is the central angle in degrees and r is the radius.

Therefore, knowing that:

C=30\°\\r=\frac{6mi}{2}=3mi

When you substitute values, you obtain the following result:

A=(3mi)^2\pi(\frac{30\°}{360})

A=2.35mi^2

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Answer the questions below.
DedPeter [7]

Answer:

63 m

Step-by-step explanation:

Perimeter is 276, 2L + 2W = 276, so L + W = 138

L = 75

138 - 75 = W

63 m

3 0
2 years ago
You are given the information that P(A) = 0.30 and P(B) = 0.40.
Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

\\ A_{1}\;and\;A_{2}

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) (1)

An extension of the former expression is:

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2}) (2)

In <em>mutually exclusive events,</em> P(A and B) = 0, that is, the events are <em>independent </em>one of the other, and we know the probability that <em>both events happen</em> <em>at the same time is zero</em> (P(A <em>and</em> B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A <em>and</em> B) is some number different from zero. Notice the difference between <em>OR</em> and <em>AND. The latter implies that both events happen at the same time.</em>

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not <em>mutually exclusive</em>, that is, there are some cases in which the events share the same probabilities in a way that these probabilities <em>must be subtracted</em> from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that <em>both events occur at the same time</em>, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities <em>without acknowledging if the events are or not mutually exclusive</em>, whereas we can certainly add the probabilities in question when we know that both probabilities are <em>mutually exclusive</em> since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive <em>does</em> provide <em>extra information</em> and we can proceed to simply add the probabilities of either event; thus, the answers are those in which <em>we need to previously know the value of P(A and B)</em>.  

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Answer:

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