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OLga [1]
4 years ago
7

A company manufactures two products. A and B on two machines, I and II. It has been determined that the company will realize a p

rofit of $3/unit of product A and $5/unit of product B. To manufacture a unit of product A requires 11 min on machine I and 7 min on machine II. To manufacture a unit of product B requires 19 min on machine I and 11 min on machine II. There are 5 hr of machine time available on machine 1 and 3 hr of machine time available on machine II in each work shift. How many units of each product should be produced in each shift to maximize the companies profit?
Mathematics
1 answer:
Andrews [41]4 years ago
4 0

Answer:

product A on machine 1 would make 27 units (rounded down) 81 dollars profit.

product A on machine 2 would make 25 units (rounded down) 75 dollars profit.

product b on machine 1 would make 15 units (rounded down) 75 dollars profit.

product b on machine 2 would make 16 units (rounded down) 80 dollars profit.

Step-by-step explanation:

a1 refers to product a on machine 1

a2 refers to product a on machine 2

same rule applies for product b 1 and 2

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A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

8 0
3 years ago
Solve the system y = -x + 7 and y = -0.5(x - 3)^2 + 8.
AlladinOne [14]

Answer:

(1,6) & (7,0)

Step-by-step explanation:

y = -x + 7

y = -0.5(x - 3)² + 8

To solve the system, solve these two equations simultaneously

-x + 7 = -0.5(x - 3)² + 8

-x + 7 = -0.5(x² - 6x + 9) + 8

-x + 7 = -0.5x² + 3x - 4.5 + 8

0.5x² - 4x + 3.5 = 0

x² - 8x + 7 = 0

x² - 7x - x + 7 = 0

x(x - 7) - (x - 7) = 0

(x - 1)(x - 7) = 0

x = 1, 7

y = -1 + 7 = 6

y = -7 + 7 = 0

(1,6) (7,0)

Since the system has two distinct solutions, the line and the curve meet at two distinct poibts9: (1,6) & (7,0)

8 0
3 years ago
There are four red ,four blue, and two green marbles in a bag .if one marble is chosen at random from the bag what is the probab
mina [271]

Answer:

There is a 20% probablity that the marble will be green :)

Step-by-step explanation:

  • There are a total of 10 marbles in the bag. 4 red+4 blue+ 2green=10
  • There are two green marbles out of the 10 marbles.  2/10
  • 2 divided by 10 is .20 or 20%
  • Therefore, there is a 20% probability that the marble will be green.
7 0
3 years ago
Does this look good??????
VLD [36.1K]

Answer:

It should be RGB that's a L

Step-by-step explanation:

8 0
3 years ago
What is the interest if a sum of $5200 is invested for 36month at 15% per annum​
Serggg [28]

Answer:

I = 2,340

Step-by-step explanation:

The formula for interest is

I = P × R × T / 100

P = $5200

R = 15%

T= 36 months; T is meant to be in years so we will convert it from months to years

1 year = 12 months

So 36 months

= 36 /12 = 3 years

I = (5200 × 15 × 3)/100

I = 234,000 / 100

I = 2,340

4 0
4 years ago
Read 2 more answers
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