Given the following linear function sketch the graph of the function and find the domain and range.
1 answer:
Answer:
see the procedure
Step-by-step explanation:
we have
This is the equation of a line in slope intercept form
where
----> the slope
----> the y-coordinate of y-intercept
To graph the line find out the intercepts
The y-intercept is the point (0,7) ----> given value
The x-intercept is the point (2.33,0) ---> Remember that the x-intercept is the value of x when the value of the function is equal to zero
with the points (0,7) and (2.33,0) sketch the graph
using a graphing tool
Plot the points and join to graph the line
see the attached figure
The domain is all real numbers
The range is all real numbers
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Price elasticity is defined as 
.
Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0
We calculate
by implicit differentiation with respect to p:
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)
Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)
Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0
We calculate
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)
Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)