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vaieri [72.5K]
2 years ago
12

As an estimate we are told 5 miles is 8 km, what is 62.5 miles into km

Mathematics
1 answer:
Sati [7]2 years ago
6 0

Answer:

≈100.5

Step-by-step explanation:

hope this helps

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I just made a purchase of $130.00 but once I got my car and looked at the receipt, I realized the salesperson who helped me did
Andrej [43]

Answer:

Guessing you want me to figure out what your cost should have been. On it!

Step-by-step explanation:

130 * .15 = 19.5

130 - 19.5 = $110.5

That should be the new cost.

5 0
1 year ago
Lionel gave 1/2 of his baseball cards to Rick. He gave his brother 1/2 of what was left. He then had 12 cards left. How many did
Salsk061 [2.6K]
C. 48

If Lionel started with 48, and he gave 1/2 of them to Rick (24), then he is left with 24. If he then gives his brother 1/2 of that (12) then he has 12 left.
5 0
3 years ago
Read 2 more answers
Use the distributed property to simplify the expression 6(x+4)+1
valkas [14]

Answer:

6x + 25

Step-by-step explanation:

6(x + 4) + 1

6x + 24 + 1

6x + 25

4 0
2 years ago
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In the figure, what percentage of the circles are shaded?
Artist 52 [7]
25% of the circles are shaded. You would find this by dividing 3/12! Have a good day!
4 0
3 years ago
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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
3 years ago
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