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mixer [17]
3 years ago
8

What is the solution to the system of linear equations?

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

x = 5, y = -1/2

Step-by-step explanation:

3.5x - 5y = 20

3x + 4y = 13 multiply by 1.25 so the y's match up (you could match x's too)

3.75x + 5y = 16.25

–––––––––––––––––––––––

3.5x - 5y = 20

3.75x +5y = 16.25

7.25x + 0y = 36.25 you can add or subtract here (on this equation you add)

7.25x=36.25

x=5 So now we have x=5 and to find y we can just plug in x into one of the equations

–––––––––––––––––––

3(5) + 4y = 13

15 + 4y = 13

4y = -2

y = -1/2

x = 5, y = -1/2

Then you can plug in both to check your answers.

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Estimate the square root of 397 between two consecutive whole numbers.
marshall27 [118]

Answer: 19.9248588452

Step-by-step explanation:

5 0
3 years ago
Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Ymorist [56]

The 40 ml solution is said to be created from 10 ml and 30 ml solutions. In mixture problems, we equate the final mixture to its compositions given the concentration for each.  A 10 ml has 20% acid and the 30 ml has C (unknown). We can write the total liters for 10 ml as 10(.2) and 30(c) for the 30 ml. when two solutions were added, it should be equal to 40ml with 32% acid. Therefore, it should be written as 10(.2) + 30(c) = 40(.32). The answer is A

7 0
3 years ago
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Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
78 : 120 :: ? : 66<br>please give answer with explanation<br>​
yawa3891 [41]

Step-by-step explanation:

<u>Method</u><u> </u><u>1</u><u>:</u>

Given that:

78 : 120 :: ? : 66

Here,

Product of extremes = 78 and 66

Product of means = 120 and ?

so,

(78*66) = (120 * ?)

⇛5148 = 120 * ?

⇛5148 = 120?

⇛120? = 5148

Shift the number 120 from LHS to RHS, changing it's sign.

⇛? = 5148/120

Therefore, (?) = 42.9

<u>Method</u><u> </u><u>2</u><u>:</u>

78 : 120 :: ? : 66

Convert each ratio into fraction.

⇛78/120 = ?/66

On applying cross multiplication then

since, (a/b) = (c/d) ⇛cd = ad

Where, a = 78, b = 120, c = ? and d = 66

Now,

⇛(120)? = (78)66

⇛120? = 5148

⇛(?) = 5148/120

Therefore, (?) = 42.9

<u>Ans</u><u>w</u><u>er:</u> Hence the value of (?) for the given problem is 42.9.

<u>Verification</u><u>:</u>

Check whether the value of (?) is true or false.

78 : 120 :: ? : 66

Substitute the value of (?).

⇛78:120 = 42.9:66

Product of extremes should be equal to product of means.

Product of extremes:- 78*66 = 5148

Product of means:- 120*42.9 = 5148

⇛5148 = 5148

LHS = RHS

Hence, verified.

4 0
2 years ago
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Ugo [173]

(a) 7 x 5 = 35 - 15 = $20

(b) 20 / 4 = 5 days

3 0
3 years ago
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