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3 years ago

What is the solution to the system of linear equations?

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

4 0

Answer:

x = 5, y = -1/2

Step-by-step explanation:

3.5x - 5y = 20

3x + 4y = 13 multiply by 1.25 so the y's match up (you could match x's too)

3.75x + 5y = 16.25

–––––––––––––––––––––––

3.5x - 5y = 20

3.75x +5y = 16.25

7.25x + 0y = 36.25 you can add or subtract here (on this equation you add)

7.25x=36.25

x=5 So now we have x=5 and to find y we can just plug in x into one of the equations

–––––––––––––––––––

3(5) + 4y = 13

15 + 4y = 13

4y = -2

y = -1/2

x = 5, y = -1/2

Then you can plug in both to check your answers.

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You start driving west for 3 miles, turn right, and drive north for another 11 miles. At

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14 miles Substitute AB = 3 and BC = 11 in above equation.

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2 years ago

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Find the value of c that makes x^2–6x + c a perfect square trinomial and write as a binomial squared.

denpristay [2]

Answer: 9

Step-by-step explanation:

Given

The function is $x^2-6x+c$

To make it a perfect square, compare it with $(a-b)^2=a^2+b^2-2ab$

Here,

$x=a,\\-6x=-2ab\\\\\therefore b=3$

So, c must be square of b i.e. 9

$x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2$

Therefore, value of c is 9.

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3 years ago

What is 1/2k-3=2-3/4K

laiz [17]

Answer:

1/2k-3=2-3/4k

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1.25k/1.25=5/1.25

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3 years ago

If the angle ZYX measures 45 degrees ,then arc XY measures 45 degrees. TRUE OR FALSE ?!

Angelina_Jolie [31]

The picture in the attached figure

the correct question is
<span>If the angle ZYX measures 45 degrees, then arc XZ measures 45 degrees. TRUE OR FALSE ?!

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3 years ago

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

So, no option is correct. And the answer is

$T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

Learn more about linear transformations here-

brainly.com/question/13005179

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2 years ago