1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
1. 7 + -10 = -3.
2. -3 + -8 = -11
3. 4 + -5 = -1
4. 2 + -6 = -4
(You basically need to add negative numbers to positive numbers in order to get negative numbers.)
X⁴ + x³ - 2x² + x + (2x⁴ - 2x²<span> - 3) =
</span>x⁴ + x³ - 2x² + x + 2x⁴ - 2x² - 3 =
3x⁴ + x³ - 4x² + x - 3 ← <span>the missing polynomial</span>
Answer:
17
Step-by-step explanation:
√25 = 5
√144 = 12
5 + 12 = 17
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