We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students

To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
225/3 = 75
75 x 5 = 375
Hope this helps.
Answer:
The answer is y = 5x +2
Step-by-step explanation:
Circumference = 2πr
r = 9
Circumference = 2π(9)
Circumference = 18π
Circumference = 18(3.14)
Circumference = 56.52
Distance: 56.52 meters