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geniusboy [140]
4 years ago
5

Complete the electron configuration for a radium atom (z = 88) in the ground state.

History
1 answer:
igomit [66]4 years ago
6 0

The electronic configuration for Radium at ground state would be this one: but first, the ground state electron configuration is the organization of electrons all over the nucleus of an atom with lesser energy levels.

 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p64f14 5d10 6s2 6p6 7s²  or in other terms [Rn] <span>7s2</span> and the term symbol is 1S0.

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=223−414=223−414

Rewriting our equation with parts separated

=2+23−4−14=2+23−4−14

Solving the whole number parts

2−4=−22−4=−2

Solving the fraction parts

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Find the LCD of 2/3 and 1/4 and rewrite to solve with the equivalent fractions.
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Combining the whole and fraction parts

−2+512=−1712−2+512=−1712

Solution by Formulasc onverting mixed numbers to fractions, our initial equation becomes,

83+−17483+−174

Applying the fractions formula for addition,

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=32+−5112=32+−5112

=−1912=−1912

Simplifying -19/12, the answer is

=−1 7/12


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