Describe relathionship between the values of given digits. The 6's in 6600

Determine if Ginny factored correctly. If not, explain where she made an error. Ginny made a mistake in step 1 when she identifi

il63 [147K]

Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

$6x^2 - 31x -30 = 0$

As we can see that the value of constants are,

a = 6

b = -31

c = 30

$6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0$

Therefore, the factors of the trinomial $6x^2 - 31x -30 = 0$ are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

brainly.com/question/17177510

3 0

2 years ago

Read 2 more answers

What times what equals 120 and When you add the two numbers they equal 26?

Alona [7]

6 times 20 equals 120 and equals 26 when added together

3 0

3 years ago

A small motorboat travels 12mph in still water. It takes 2 hours longer to travel 46 miles going upstream than it does going dow

Natasha_Volkova [10]

Using the relation between velocity, distance and time, it is found that the rate of the current is of 3.33 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is distance divided by time, hence:

v = d/t

A small motorboat travels 12mph in still water. With the current, upstream, 46 miles are traveled in t hours, hence:

12 + r = 46/t

r = 46/t - 12

Downstream, the time is of t + 2 hours, hence:

12 - r = 46/(t + 2)

r = 12 - 46/(t + 2)

Hence, equaling the values for r:

46/t - 12 = 12 - 46/(t + 2)

46/t + 46/(t + 2) = 24

$\frac{46t + 92 + 46t}{t(t + 2)} = 24$

92t + 92 = 24t² + 48t

24t² - 44t - 92 = 0

Using a quadratic equation calculator, the solution is t = 3. Hence the rate is found as follows:

r = 46/t - 12 = 46/3 - 12 = 3.33 mph.

More can be learned about the relation between velocity, distance and time at brainly.com/question/28155966

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4 0

2 years ago

SOMEONE PLZ HELP ME!!!! I WILL GIVE BRAINLIEST!!!

MAXImum [283]

Answer:

Step-by-step explanation:

Let the quadratic equation of the function by the points in the given equation is,

f(x) = ax² + bx + c

If the points lying on the graph are (-3, -10), (-4, -8) and (0, 8),

For (0, 8),

f(0) = a(0)² + b(0) + c

8 = c

For a point (-3, -10),

f(-3) = a(-3)² + b(-3) + 8

-10 = 9a - 3b + 8

9a - 3b = -18

3a - b = -6 --------(1)

For (-4, -8),

f(-4) = a(-4)² + b(-4) + 8

-8 = 16a - 4b + 8

-16 = 16a - 4b

4a - b = -4 ------(2)

Subtract equation (1) from equation (2)

(4a - b) - (3a - b) = -4 + 6

a = 2

From equation (1),

6 - b = -6

b = 12

Function will be,

f(x) = 2x² + 12x + 8

= 2(x² + 6x) + 8

= 2(x² + 6x + 9 - 9) + 8

= 2(x² + 6x + 9) - 18 + 8

= 2(x + 3)² - 10

By comparing this function with the vertex form of the function,

y = a(x - h)² + k

where (h, k) is the vertex.

Vertex of the function 'f' will be (-3, -10)

And axis of symmetry will be,

x = -3

From the given graph, axis of the symmetry of the function 'g' is; x = -3

Therefore, both the functions will have the same axis of symmetry.

y-intercept of the function 'f' → y = 8 Or (0, 8)

y-intercept of the function 'g' → y = -2 Or (0, -2)

Therefore, y-intercept of 'f' is greater than 'g'

Average rate of change of function 'f' = $\frac{f(b)-f(a)}{b-a}$ in the interval [a, b]

= $\frac{f(-3)-f(-6)}{-3+6}$

= $\frac{-10-8}{3}$

= -6

Average rate of change of function 'g' = $\frac{g(b)-g(a)}{b-a}$

= $\frac{g(-3)-g(-6)}{-3+6}$

= $\frac{7+2}{-3+6}$

= 3

Therefore, Average rate of change of function 'f' is less than 'g'.

6 0

3 years ago

Under which condition does a light ray striking a concave mirror reflect off parallel to the principal axis?. . . A. when the in

kumpel [21]

When the incident ray passes through the focal point, a light ray striking a concave concave mirror reflect off parallel to the principal axis. The correct option among all the options given in the question is the third option or option "C". I hope the answer comes to your help.

5 0

3 years ago