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soldier1979 [14.2K]
4 years ago
15

For each table of values, select whether the table represents a linear or exponential relationship. Please help 10 points for th

e answer

Mathematics
1 answer:
natali 33 [55]4 years ago
8 0

We have a Table here called Function A. So we need to know whether the table represents a linear or exponential relationship. Remember that:

A linear function has the form:

f(x)=mx+b so if x increases by a constant amount the functions value will have a common difference.

An exponential function has the form:

f(x)=ab^x so if x increases by a constant amount the functions value will have a common difference.

<h2>FUNCTION A)</h2>

EXPONENTIAL RELATIONSHIP.

Notice that in this case the function increases by a constant amount and in this case this amount is 3 because:

6-3=3 \\ \\ 9-6=3 \\ \\ 12-9=3

As you can see, it is true that x increase by a constant amount of 3. Hence, we need to analyze the function values.

First, let's see if the function values has a common difference:

9.252-6.083=3.169 \\ \\ 14.07-9.252=4.818 \\ \\ Stop \ here!

We have stopped because there is no any common difference. Let's try to see if there is common ratio:

\frac{9.252}{6.083}=1.52 \\ \\ \frac{14.07}{9.252}=1.52 \\ \\ \frac{21.4}{14.07}=1.52

As you can see these function values have a common ratio. In conclusion THIS TABLE REPRESENTS AN EXPONENTIAL RELATIONSHIP.

<h2>FUNCTION B)</h2>

LINEAR RELATIONSHIP.

From the Table, it's easy to realize that this is a linear relationship by taking a look on the function values. Notice that x increases here at a constant amount of 2 because:

6-4=2 \\ \\ 8-6=2 \\ \\ 10-8=2

So, let's see if the function values has a common difference:

14-7=7 \\ \\ 21-14=7 \\ \\ 28-21=7

As you can see these function values have a common difference. In conclusion THIS TABLE REPRESENTS A LINEAR RELATIONSHIP.

<h2>FUNCTION C)</h2>

EXPONENTIAL RELATIONSHIP.

It is likely that this is an exponential function, just take a look at the function values. Notice that x increases here at a constant amount of 2 because:

2-0=2 \\ \\ 4-2=2 \\ \\ 6-2=2

So, let's see if the function values has a common ratio:

\frac{4}{16}=0.25 \\ \\ \frac{1}{4}=0.25 \\ \\ \frac{0.25}{1}=0.25

As you can see these function values have a common ratio. In conclusion THIS TABLE REPRESENTS AN EXPONENTIAL RELATIONSHIP.

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What is the answer to the question below, I have been working on it for a while. Plz help!
Vsevolod [243]

Answer:

10m / 7

Step-by-step explanation:

times = multiplication of 10 and variable m

quotient of = division of 7

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You and some friends are going to the fair. Small rides costs 4 tickets and while big rides costs 7 tickets. You and your friend
tensa zangetsu [6.8K]

Answer:

<em>4x+7y≤250</em>

Step-by-step explanation:

<u>Inequalities</u>

Let's call:

x = number of small rides

y = number of big rides

Since each small ride costs 4 tickets, x rides cost 4x tickets.

Since each big ride costs 7 tickets, y rides cost 7y tickets.

The total number of tickets is the sum of both:

Total tickets = 4x+7y

The friends have 250 tickets, so the total tickets of the rides cannot be greater than the 250 tickets available, thus:

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3 years ago
Find the probability of rolling an odd sum or a sum less than 7 when a pair of dice is rolled
Nutka1998 [239]

Answer:

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

Step-by-step explanation:

For this case when a pair of dice is rolled we have the following sample pace for the outcomes:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

We see 36 possible outcomes and we want to find how many of these pairs we got rolling an odd sum or a sum less than 7

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

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3 years ago
shanice won 88 pieces of gum playing the bean bag toss at the country fair. At school she gave four to every student in her math
CaHeK987 [17]
22 mate
hope this helps :) <span>®™©</span>
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