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3 years ago

13

Simon and Andrew see a speed limit sign that says 65 kilometers per hour. They decide to convert this speed limit to miles per h

our. They each do the conversion separately and come up with different answers. Their work is shown. Who is correct? Explain.

1 answer:

stealth61 [152]3 years ago

5 0

Answer:

40.38912735 or about 40 miles per hour (rounded to the nearest whole number)

Step-by-step explanation:

1.) You want to convert kilometers per hour to miles per hour.

2.) There are 0.62137119 miles in 1 kilometer.

3.) Multiply 65 by 0.62137119

4.) That equals 40.38912735

5.) This answer can be rounded to 40 mph.

You might be interested in

Write 2/4 in simplest form

Bas_tet [7]

Divide both sides by their LCD, 2

2/4 = 1/2

1/2 is irreducible

8 0

3 years ago

Identify the percent of change an increase or decrease then find percent of change one hundredfifty pounds to one hundred thirty

Alex777 [14]

Answer:

−10%change

10%decrease

Step-by-step explanation:

V2−V1)|V1|×100

=(135−150)|150|×100

=−15150×100

=−0.1×100

=−10%change

=10%decrease

Note: Percent Change is NOT the same as Percent Difference between 150 and 135.

Hope this helps!

6 0

3 years ago

Mrs. Santiago is buying bagels for her office.Each box contains 6 plain, 4 blueberry, and2 onion bagels. Write and interpret a r

yawa3891 [41]

Explanation:

Each box contains

$\begin{gathered} 6plain \\ 4blueberry \\ 2onionbagels \end{gathered}$

The ratio that compares the number of blueberry bagels in one box to the number of onion bagels in one box will be calculated below as

$\begin{gathered} 4:2 \\ in\text{ the simplest form } \\ 2:1 \end{gathered}$

This means that for every one onionbagels in the box, there are 2 blueberry bagels

Part B:

Given that there are 20 blueberry bagels, the number if onion bagels will be calculated below as

$\begin{gathered} \frac{2}{1}=\frac{20}{x} \\ cross\text{ multiply, we will have} \\ 2x=20 \\ \frac{2x}{2}=\frac{20}{2} \\ x=10 \end{gathered}$

Hence,

The final answer is

$10\text{ }onion\text{ }bagels$

7 0

1 year ago

Please help very urgent

Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

A cylinder has a base diameter of 14m and a height of 15m. What is its volume in

BabaBlast [244]

Answer:

2310m^3

Step-by-step explanation:

base area which is the circle = πr^2

But diameter, d = 14, r = 14/2 = 7

area = π × (7)^2 = 22/7 × 49 = 22 × 7 = 154

Volume = base area × height

= 154 × 15 = 2310

3 0

3 years ago