When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
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Answer:
16 (1+2)
Step-by-step explanation:
factors of 16: 1,2,4,8,16
factors of 32: 1,2,4,8,16,32
16 x 1 = 16
16 x 2 = 32
Answer:
Set
−
3
+
3
√
3
i
equal to
0
.
−
3
+
3
√
3
i
=
0
Since
−
3
+
3
√
3
i
≠
0
, there are no solutions.
Step-by-step explanation:
Answer:
Yes it does
Sorry I need 20 characters so 2+2=4 there you go
Given that the triangle is dilated by factor 3, the image will be found as follows;
The object is at:
A(-7,-3), B(-3,-2), C(-4,-5)
when the image was enlarged the new coordinates will be:
A'=3(-7,-3)=(-21,-9)
B'=3(-3,-2)=(-9,-6)
C'=3(-4,-5)=(-12,-15)
since the image is centered at the point (-7,-6), the final point will be at:
A"=[(-21+-7),(-9+-6)=(-28,-15)
B''=[(-9+-7),(-6+-6)]=(-16,-12)
C''=[(-12+-7),(-15+-6)]=(-19,-17)
thus the coordinates of the final image are:
A''(-28,-15),B''(-16,-12),C''(-19,-17)
