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Oliga [24]
3 years ago
6

A vehicle travels at a steady rate of 35 miles per hour. A student will graph the total distance, D, as a function of the time i

n hours, h, showing the distance for 1 to 3 hours. If the student counts by 10's, what should be the largest value on the D-axis of his or her graph so that the scale is the most appropriate for the given information?

Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

Solution:

Speed of Vehicle which travels at steady rate = 35 miles per hour

As we know , Distance = Speed × Time

For , Time = 1 Hours

Distance traveled = 35 miles per hour × 1 Hour = 35 miles

Time =  2 Hours

Distance traveled = 35 miles per hour × 2 Hour = 70 miles

Time = 3 Hours

Distance traveled = 35 miles per hour × 3 Hour = 105 miles

So points which are represented as ⇒ (Distance , Time) is (1,35),(2,70), (3,105).

We can find the equation of line using two point formula.

\frac{y-35}{x-1}=\frac{70-35}{2-1}\\\\y-35=35(x-1) \\\\y - 35 = 35 x -35 \\\\ y = 35 x

For , T = 10's = \frac{10}{60} = \frac{1}{6} Hour

y = 35 \times \frac{1}{6}= 6 miles (approximately)

1 unit = 6 miles (on D axis, i.e Y axis.)

To locate 105 on D axis , Largest value on D axis= \frac{105}{6}=17.5 Units

The largest value on the D-axis of his or her graph so that the scale is the most appropriate for the given information is 17.5 i.e Y axis.


scZoUnD [109]3 years ago
6 0
110 is the answer i got it wrong on my test and that was it.
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Genrish500 [490]

Answer:

  • 24 km/h

Step-by-step explanation:

  • The speed of the boat  in the lake = x
  • The speed of the current = 3 km/h

<u>Required equation:</u>

  • 54 / (x + 3) + 42 / (x - 3) = 96/x
  • 9x(x - 3) + 7x(x + 3) = 16(x + 3)(x - 3)
  • 9x² - 27x + 7x² + 21x = 16x² - 144
  • 6x = 144
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7 0
3 years ago
A culture started with 3000 bacteria. After 4 hours, it grew to 3,600 bacteria. Predict how many bacteria will be present after
Vlad [161]
Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.

A = A_ob^t
3600 = 3000b^4

Now we solve for b
3600 = 3000b^4
\frac{3600}{3000} = \frac{3000b^{4}}{3000}
\frac{6}{5} = b^4
\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}
\sqrt[4]{\frac{6}{5}} = b

Now that we have found b, we can use the equation A = 3000b^t to predict how many bacteria will be present after 10 hours.
b = \sqrt[4]{\frac{6}{5}}
t = 10
A = 3000b^t
A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732

Answer = 4732



4 0
3 years ago
A year is a leap year if it is divisible by 4. but if the year is divisible by 100, it is a leap year only when it is also divis
KIM [24]
What is the question that you are asking?
3 0
3 years ago
HELP HELP HELP
mojhsa [17]

Answer:

2998 ; 17%

Step-by-step explanation:

Given the function:

t(c)=-3970.9(ln c)

c = % of carbon remaining ; t = time

1.) c = 47% = 47/100 = 0.47

t(0.47) = - 3970.9(In 0.47)

t = - 3970.9 * −0.755022

t = 2998.119

t = 2998

B.)

t = 7000

t(c)=-3970.9(ln c)

7000 = - 3970.9(In c)

7000 / - 3970.9 = In c

−1.762824 = In c

c = exp(−1.762824)

c = 0.1715596

c = 0.1715596 * 100%

c = 17.156% ; c = 17%

8 0
3 years ago
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Solve by using factorizing method:4x²-36x+81=0​
boyakko [2]

Answer:

  • x = 4.5

Step-by-step explanation:

  • 4x² - 36x + 81 = 0​
  • (2x)² - 2*2x*9 + 9² = 0           Identity  a² - 2ab + b² = (a - b)²
  • (2x - 9)² = 0
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8 0
3 years ago
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