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kykrilka [37]
3 years ago
10

(x + 5 1/2) 0.75= 5/8 What is x?

Mathematics
1 answer:
swat323 years ago
7 0
<span>(x + 5 1/2) 0.75= 5/8<span>
Convert 0.75 into a fraction
</span></span><span>(x + 5 1/2) 3/4= 5/8
Use distributive property
3/4x + 5 1/2*3/4 = 5/8
Convert 5 1/2 into improper fraction
3/4x + 11/2*3/4 = 5/8
Multiply
3/4x + 33/8 = 5/8
Subtract 33/8 from both sides
3/4x = 5/8 - 33/8
Subtract the numerators but NOT the denominators
3/4x = -28/8
Divide 3/4 on both sides
x = -28/8 divided by 3/4
Convert the division sign to multiplication while flipping the fraction 3/4 to 4/3
x = -28/8 * 4/3
Multiply
Final Answer: x = -112/24 or -4 16/24 or -4 4/6 or -4 2/3 *All answers are equivalent to each other.</span>
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Please help fast <br>need it by today
KiRa [710]
6. It is asking you to find the surface area for this one:

1 litre = 0.001 cubic meters
15.4 litres = 0.0154 cubic meters

The volume of the cylinder has to be 0.0154m^3.

V = (pi(r)^2)h
0.0154 = (pi(r)^2)(1)
r^2 = 0.0154/pi
r = 0.07m

Surface Area of Circles on Bottom:
A = pi(r)^2
A = pi(0.07)^2
A = 0.0154
0.0154*2 = 0.0308m^2

Surface Area of Walls:
This will be the circumference of the circle times the height, since the walls are just like a big rectangle.

C = 2pi(r)
C = 2pi(0.07)
C = 0.44m
0.44*1 = 0.44m^2

Finally, add the two surface areas:
0.44 + 0.0308 = 0.47m^2

You will need 0.47m^2 of sheet metal to make this cylinder.

7. Find the volume of everything and just the graphite, and subtract the graphite’s volume from everything to get just the wood. The volume of a cylinder is pi((r)^2)h.

Everything:
Watch out for units, since the diameter is in mm and the length is in cm.

r = 3.5mm or 0.35cm
V = pi((0.35)^2)(14)
V = 5.34cm^3

Graphite:

r = 0.5mm or 0.05cm
V = pi((0.05)^2)(14)
V = 0.11cm^3

5.34 - 0.11 = 5.23cm^3

8. For this problem, it wants your answer in cm^3. Find the volume of one bowl and multiply it by 250:

r = 3.5cm
V = pi((3.5)^2)(4)
V = 153.94cm^3

153.94*250 = 38484.51cm^3 of soup needed.

I sure hope that I didn’t confuse you too much with all of my math gibberish (sorry). Please let me know if there is anything else that I can help with. Have a nice day
3 0
3 years ago
Emily measured the height of a dresser as 4.27 feet, but the actual height was 4 feet. What is the percentage of error in Emily’
Assoli18 [71]
We need to find the percentage of the extra feet that she measured, so first we have to find out how much that is. We can do this by simply subtracting:

4.27 - 4 = 0.27

Now we can set up a proportion to find the percentage.

\frac{0.27}{4}  \frac{x}{100}

Solve for x

0.27 x 100 = 27
27/4 = 6.75

The answer is 6.75% :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
6 0
3 years ago
Why is the answer B? Plz explain.
Ivanshal [37]

Step One

Develop a formula for the perimeter.


Argument

What you see is a semicircle going upwards and another one going downwards. Two semicircles =1 circle.


The "perimeter" [Circumfrence] of a whole circle = 2*pi*r


We are told that whatever you call this the perimeter is 8pi + 16


Step Two

Set up the equation

8pi + 16 = 2*pi*r + 4r Including the line connecting these two.


Step Three

Take out the common factors on the left and right.


8(pi + 2) = 2r(pi + 2) Divide both sides by pi + 2

8 = 2r Divide by 2

4 = r


Sorry. I didn't know the meaning of perimeter. Mathmate is perfectly correct.

6 0
3 years ago
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fredd [130]

Answer: (x^2-7)/(2x+1) \color(red)(f(x)=2x+1) and \color(blue)(g(x)=x^2-7) Thus, we have: (g/f)(x)=\color(blue)(g(x))/\color(red)(f(x))=\color(blue)(x^2-7)/\color(red)(2x+1)

Step-by-step explanation:

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2 years ago
Please Help I Don't Understand!!!! WILL GIVE BRAINLIEST ANSWER!
kondor19780726 [428]
Rationalising the denominator is what I would do (figure may imply differently) if x= 9/root 3, then times both the denominator and numerator by Root3, leaving 9*root3/Root3*Root3

This cancels down into 9*Root3/3 because a root*root of the same number= that number

9 times Root 3 all over 3
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4 years ago
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