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aleksklad [387]
3 years ago
8

The table lists several points that form a line on a coordinate plane.

Mathematics
1 answer:
omeli [17]3 years ago
6 0

Answer:

Slope is 1/4 (0.25) while y-intercept is 5

Step-by-step explanation:

Here, we are interested in getting the y intercept and slope of the line joining the given points.

We can get the slope by using any two points

Let’s say (4,6) and (12,8)

Mathematically; slope

= (y2-y1)/(x2-x1) = (8-6)/(12-4) = 2/8 = 1/4 = 0.25

To get the y-intercept, we proceed

kindly recall that the equation of a straight line is;

y = mx + c

where m is the slope and c is the y-intercept

Let’s take any of the points (28,12)

Thus:

12 = 0.25(28) + c

12 = 7 + c

c = 12-7

c = 5

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There were 632 animals gathered at the river. A herd of 187 elephants and 266 zebras left the river area. How many animals were
Orlov [11]

Answer:

179 animals were still at the river

Step-by-step explanation:

There were 632 animals at the river.

A herd of 187 elephants and 266 zebras left the river area.

This means that 187 + 266 = 453 animals left the river area.

Remaining:

632 - 453 = 179

179 animals were still at the river

3 0
3 years ago
How do I reduce 3 and 25/21
Anarel [89]

If it's a mixed fraction, then:

3 0
4 years ago
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
4 years ago
Simplify the answer (3 to the 4th power and (3 to the negative 6th power)​
AlladinOne [14]
3^4 and 3^-6
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WILL GIVE BRAINLIEST AND 20 POINTS<br><br> Please solve this page
guajiro [1.7K]
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Read 2 more answers
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