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Elodia [21]
3 years ago
9

Please help me!!! Will get brainliest!!!

Mathematics
2 answers:
Sloan [31]3 years ago
6 0
Using the formula
A = Pe^kt
Where A is the ending amount of population, P is the population k is a constant and 't' is time.

A = 0.39, t= 12 and p= 0.29
0.39= 0.29e^12k
1.34 = e^12k
ln1.34 = 12k
ln1.34/12 = k
K= 0.02

No the graph does not support his claim as k should be equal to 0.5
Delicious77 [7]3 years ago
3 0
Yes the graph supports his claim. the bar on the left is twice as big as the bar on the right.
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In a mixture of​ concrete, there are fourfour lb of cement mix for each pound of gravel. If the mixture contains a total of 2952
Anton [14]

Answer: there are 59059 lbs of gravel.

Step-by-step explanation:

In a mixture of​ concrete, there are four lbs of cement mix for each pound of gravel. This means that eight lbs of cement would be mixed for 2 pounds of gravel and 12 lbs of cement would be mixed for 3 pounds of gravel and 12. Therefore, the constant ratio of cement to gravel is 4:1

The total ratio is 4 + 1 = 5

If the mixture contains a total of 295295 lb of these two​ ingredients, then the number of pounds of gravel that are​ there is

1/5 × 295295 = 59059 lbs

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3 years ago
What point divides directed line segment
Goshia [24]
(22.5,30) it's the ratio
6 0
3 years ago
A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of
jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

Radius of gyration x = y =  \frac{R}{4}

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0
4 years ago
26. A(-4, -1), B(-4, 6), C(2,6), D(2, -4)
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Answer:

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Step-by-step explanation:

5 0
2 years ago
Line ef is tangent to circle g at point h. segment gh is a radius of circle g. what can be concluded about triangle fhg?
solong [7]
We know that

A line tangent to a circle is perpendicular to the radius to the point of tangency.
so
<span>Line ef is </span>perpendicular to the segment gh

hence
Triangle FHG is a right triangle
3 0
3 years ago
Read 2 more answers
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