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2 years ago

Help pls need help show your solution and then graph

Mathematics

1 answer:

Stella [2.4K]2 years ago

5 0

Answer:

Step-by-step explanation:

We can use the quadratic formula or factor, This looks hard to factor so we should use the quadratic formula.

ax^2 + bx + c

a=4

b=-9

c=2

you can try it by hand or use this:

https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php

you get x=2 and x=0.25 these are the x intercepts (where Y is zero and where the graph crosses the x axis)

so mark x=2 and x=0.25 with a dot on a number line and you can draw a straight line between them since that is the part of the graph that is below the x axis (because the equation has <0) it is a positive parabola because the "a" value is positive and the presence of a "b" value means part of the graph will be below the x axis

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I think the answer is 24

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3 years ago

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In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each

Rudiy27

Answer:

$N(t) = 972(1.015)^{t}$

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

$N(t) = N(0)(1+r)^{t}$

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that $N(0) = 972$

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that $r = 0.015$

Then

$N(t) = N(0)(1+r)^{t}$

$N(t) = 972(1+0.015)^{t}$

$N(t) = 972(1.015)^{t}$

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

$N(t) = 972(1.015)^{t}$

$N(12) = 972(1.015)^{12}$

$N(12) = 1162$

The number of students enrolled in 2014 is 1162.

7 0

3 years ago

After being rearranged and simplified, which of the following equations could

masha68 [24]

Answer:

C and D

Step-by-step explanation:

The quadratic formula is

x= (-b±√b²-4ac)/2a

The formula uses the numerical coefficients in the quadratic equation.

The general quadratic equation is ax²+bx+c where a, b and c are the numerical coefficients

So, lets try and see;

$5x+4=3x^4-2\\\\=3x^4-5x-2-4\\=3x^4-5x-6\\a=3,b=-5,c=-6$

But due to the fact that in this equation you have x⁴, the equation is not a quadratic equation thus can not be solved using this formula

$-x^2+4x+7=-x^2-9\\\\\\=-x^2+x^2+4x+7+9\\=4x+16$

$9x+3x^2=14+x-1\\\\\\=3x^2+9x-x-14+1\\\\=3x^2+8x-13\\\\\\a=3,b=8,c=-13\\$

$2x^2+x^2+x=30\\\\\\=3x^2+x-30\\\\\\a=3,b=1,c=-30$

From the checking above, the equations will be C and D

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3 years ago

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Anvisha [2.4K]

Answer

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3 years ago

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tail

WINSTONCH [101]

Answer: Two-tailed test.

Population mean is the parameter which is tested.

Step-by-step explanation:

Given : $H_0: \mu=105$

$H_1:\mu\neq105$

We know that , the alternative hypothesis ( $H_1$ ) indicates kind of the hypothesis test we need to perform whether left-tailed, right-tailed, or two-tailed.

Here, the alternative hypothesis ( $H_1$ ) is two-tailed, so the hypothesis test is a two-tailed test.

Also, the parameter present in the hypothesis is $\mu$ which is a symbol to represent the population mean.

Thus , Population mean is the parameter which is tested.

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3 years ago

Help pls need help show your solution and then graph​

Help pls need help show your solution and then graph