Answer: A, x = square root of 60.
Step-by-step explanation:
Use the Pythagorean Theorem, a^2 + b^2 = c^2.
8^2 = 2^2 + x^2
x^2 = 8^2 - 2^2
x^2 = 64 - 4
x^2 = 60
x = sqrt of 60
Answer:
.
Step-by-step explanation: Given expression : ![\frac{sin \theta \ sec \theta }{cos \theta \ tan \theta} .](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20%5Ctheta%20%5C%20sec%20%5Ctheta%20%7D%7Bcos%20%5Ctheta%20%5C%20tan%20%5Ctheta%7D%20.)
We know,
![sec \theta = \frac{1}{cos \theta}](https://tex.z-dn.net/?f=sec%20%5Ctheta%20%3D%20%5Cfrac%7B1%7D%7Bcos%20%5Ctheta%7D)
![tan \theta = \frac{sin \theta}{cos \theta}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7Bsin%20%5Ctheta%7D%7Bcos%20%5Ctheta%7D)
Substituting those values in given expression, we get
=![\frac{sin \theta\ \frac{1}{cos \theta} } {cos \theta\ \frac{sin \theta}{cos \theta} }](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20%5Ctheta%5C%20%5Cfrac%7B1%7D%7Bcos%20%5Ctheta%7D%20%7D%20%7Bcos%20%5Ctheta%5C%20%5Cfrac%7Bsin%20%5Ctheta%7D%7Bcos%20%5Ctheta%7D%20%7D)
= ![\frac{sin \theta \ cos \theta}{cos \theta \ cos \theta \ sin \theta}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20%5Ctheta%20%5C%20cos%20%5Ctheta%7D%7Bcos%20%5Ctheta%20%5C%20cos%20%5Ctheta%20%5C%20sin%20%5Ctheta%7D)
Crossing out
from top and bottom, we get
=![\frac{1}{cos \theta }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bcos%20%5Ctheta%20%7D)
=
.
Answer:
-0.2 x
Step-by-step explanation:
=> 0.8x-x
<u>Taking x common</u>
=> x (0.8 - 1)
=> x (-0.2)
=> -0.2 x
This is going to be a linear function. On the horizontal axis, you will have weeks. On the vertical axis will be weeks. The slope of the line is 6/1 = 6, since she plays 6 hrs/week. At week 0 (the y-axis), the value will be 8, since that is the initial number of hours played. Therefore, the equation is: f(x) = 6x+8 f(x) is # hours x = #'d weeks.
2. All real numbers greater than 0