Question

PLeasE please help me!

Answer 1

Answer:

$\frac{3x-1}{8(x-1)}$

Step-by-step explanation:

The given expression is

$\frac{\frac{2}{x-1}+\frac{1}{x}}{\frac{8}{x} }$

The simplified form would be:

$\frac{\frac{2x+x-1}{(x-1)x} }{\frac{8}{x} }\\\frac{\frac{3x-1}{x(x-1)}}{\frac{8}{x}}\\ \frac{x(3x-1)}{8x(x-1)}\\\frac{3x-1}{8(x-1)}$

To get the simplest form, we first sum the fractions and then divided the two fractions we got.

At the end, we have the result

$\frac{3x-1}{8(x-1)}$

Where x-1 cannot be eliminated, because the variable have different variables.

Answer 2

Hey! I just took the test and the correct answer is:

3x-1/8(x-1)

Hope I helped!