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STALIN [3.7K]
4 years ago
14

Plz help me I am so stuck

Mathematics
1 answer:
kifflom [539]4 years ago
4 0

This is called a proportion. The first step to solving a proportion is cross multiplication. Next, you need to set the to products equal to each other, and solve.

The correct answer is x=4/5, or x=0.8

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[63, 9] [14, 5] [21, 3] [26, ?]<br><br> What is the unknown in this pattern, show working please.
ehidna [41]

Look :

6 + 3 = 9 ===》 [ 63 , 9 ]

1 + 4 = 5 ===》 [ 14 , 5 ]

2 + 1 = 3 ===》 [ 21 , 3 ]

2 + 6 = 8 ===》 [ 26 , 8 ]

8 0
3 years ago
Simplify this expression: 5 + 2b - 2
Stells [14]
Answer: 2b+3

Combine like terms which are 5 and -2
5 0
3 years ago
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What is the equation of the directrix of a parabola defined by the equation y = x2 − 2x − 3?
meriva
<span><span>Graph <span>x2<span> = 4</span>y</span><span> and state the vertex, focus, axis of symmetry, and directrix.</span></span><span>This is the same graphing that I've done in the past: </span><span>y = (1/4)x2</span><span>. So I'll do the graph as usual:</span></span><span> </span><span>The vertex is obviously at the origin, but I need to "show" this "algebraically" by rearranging the given equation into the conics form:<span>x2 = 4y</span> Copyright © Elizabeth Stapel 2010-2011 All Rights Reserved<span>
(x – 0)2 = 4(y – 0)</span><span>This rearrangement "shows" that the vertex is at </span><span>(h, k) = (0, 0)</span><span>. The axis of symmetry is the vertical line right through the vertex: </span><span>x = 0</span>. (I can always check my graph, if I'm not sure about this.) The focus is "p" units from the vertex. Since the focus is "inside" the parabola and since this is a "right side up" graph, the focus has to be above the vertex.<span>From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that </span><span>4p = 4</span><span>, so </span><span>p = 1</span><span>. Then the focus is one unit above the vertex, at </span>(0, 1)<span>, and the directrix is the horizontal line </span><span>y = –1</span>, one unit below the vertex.<span>vertex: </span>(0, 0)<span>; focus: </span>(0, 1)<span>; axis of symmetry: </span><span>x<span> = 0</span></span><span>; directrix: </span><span>y<span> = –1</span></span></span><span><span><span>Graph </span><span>y2<span> + 10</span>y<span> + </span>x<span> + 25 = 0</span></span>, and state the vertex, focus, axis of symmetry, and directrix.</span><span>Since the </span>y<span> is squared in this equation, rather than the </span>x<span>, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking </span>y<span>-values first and then finding the corresponding </span>x<span>-values for </span><span>x = –y2 – 10y – 25</span>:<span>To convert the equation into conics form and find the exact vertex, etc, I'll need to convert the equation to perfect-square form. In this case, the squared side is already a perfect square, so:</span><span>y2 + 10y + 25 = –x</span> <span>
(y + 5)2 = –1(x – 0)</span><span>This tells me that </span><span>4p = –1</span><span>, so </span><span>p = –1/4</span><span>. Since the parabola opens to the left, then the focus is </span>1/4<span> units to the left of the vertex. I can see from the equation above that the vertex is at </span><span>(h, k) = (0, –5)</span><span>, so then the focus must be at </span>(–1/4, –5)<span>. The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is </span>1/4<span> units to the right of the vertex. Putting this all together, I get:</span><span>vertex: </span>(0, –5)<span>; focus: </span>(–1/4, –5)<span>; axis of symmetry: </span><span>y<span> = –5</span></span><span>; directrix: </span><span>x<span> = 1/4</span></span></span><span><span>Find the vertex and focus of </span><span>y2<span> + 6</span>y<span> + 12</span>x<span> – 15 = 0</span></span></span><span><span>The </span>y<span> part is squared, so this is a sideways parabola. I'll get the </span>y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.<span>y2 + 6y – 15 = –12x</span> <span><span>
y</span>2 + 6y + 9 – 15 = –12x + 9</span> <span>
(y + 3)2 – 15 = –12x + 9</span> <span>
(y + 3)2 = –12x + 9 + 15 = –12x + 24</span> <span>
(y + 3)2 = –12(x – 2)</span> <span>
(y – (–3))2 = 4(–3)(x – 2)</span></span><span><span>Then the vertex is at </span><span>(h, k) = (2, –3)</span><span> and the value of </span>p<span> is </span>–3<span>. Since </span>y<span> is squared and </span>p<span> is negative, then this is a sideways parabola that opens to the left. This puts the focus </span>3 units to the left of the vertex.<span>vertex: </span>(2, –3)<span>; focus: </span><span>(–1, –3)</span></span>
4 0
4 years ago
Read 2 more answers
The sum of a number and 7 is the same as double the number increased by 3
koban [17]
So, let’s represent the number as n:
n+7=2n+3
Subtract both sides by 3:
n+4=2n
Now by n:
2n=4
Divide:
n=2
The number is 2
4 0
3 years ago
Read 2 more answers
If aₙ = 3(3)ⁿ⁻¹ , what is S₃?<br><br> 12<br><br> 27<br><br> 9<br><br> 39
Allushta [10]

Answer:

S_3=39

Step-by-step explanation:

The nth term of the sequence is

a_n=3(3)^{n-1}

To get the first term, substitute n=1,

a_1=3(3)^{1-1}=3

To get the second term, substitute n=2,

a_2=3(3)^{2-1}=9

To get the third term, substitute n=3,

a_3=3(3)^{3-1}=27

The sum of the first three terms is

S_3=3+9+27=39

We could also use the formula

S_n=\frac{a_1(r^n-1)}{r-1} to get the same result.

8 0
3 years ago
Read 2 more answers
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