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asambeis [7]
3 years ago
8

Multiply. ​ 3/10 × (−4/5) ​ Enter your answer as a fraction, in simplified form, in the box.

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0
The correct answer is -12/15
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Mr. Malone made a graph to represent the time his students spent studying for their tests throughout the unit and their actual t
denis-greek [22]

Answer:

a. 4/3

b. Test scores in percentage

c. y=4/3x +50

d. 78

8 0
3 years ago
Simply the following expression. (v-2+3v3^) + (4v3^+7v+3)
Nina [5.8K]

Answer:

<em>Hope</em><em> </em><em>this is</em><em> </em><em>correct</em><em> </em>

Step-by-step explanation:

HAVE A GOOD DAY!

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3 years ago
6)
Dvinal [7]

Answer:

It has to be x - 9= 27

so it can be x=36

6 0
3 years ago
Read 2 more answers
PLSSSSSSS HELPPPPPppppp
icang [17]

Answer:

20 units

Step-by-step explanation:

The polygon has 4 vertices as indicated by the 4 coordinate points given.

(3, 1) and (8, 1) is a horizontal side of length 8 - 3 = 5

Similarly

(3, 6) and (8, 6) is the opposite horizontal side of length 8 - 3 = 5

Points (3, 1) and (3, 6) is a vertical side of length 6 - 1 = 5

(8, 1) and (8, 6) is the opposite side of length 6 - 1 = 5

The polygon is therefore a square of side 5 units.

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5 0
3 years ago
Bill Ding plans to build a new hardware store. He buys a rectangular lot that is 50 ft by 200 ft, the 50-ft dimension being alon
enot [183]

Answer:

Length a = 59.62

Width b = 67.09

Cost = $10,734.4

Step-by-step explanation:

Solution:

Let a be the length and b be the width.

Area of the rectangle = a x b

a x b = 4000

Cost of the construction:

Cost = 100a + 80(a + 2b)

Cost = 100a + 80a + 160b

Cost = 180a + 160b     Equation of the Cost of the construction.

Now, we need a and b to calculate the minimum cost required to build a lot.

From the area = a x b

we have,

a x b = 4000

b = 4000/a

Putting this equation into the cost of the construction.

We get:

Cost = 180a + 160 x (4000/a)

Cost = 180a + 640000/a

Differentiating with respect to a, we get

C^{'} = 180 - 640000/a^{2}

Putting C^{'} = 0

180 - 640000/a^{2} = 0

Taking LCM

180a^{2} - 640000 = 0

Solving for a

180a^{2} = 640000

a^{2} = 640000/180

a^{2} = 3555.55

Taking square root

a = 59.62

As we know,

b = 4000/a

putting the minimum value of a  = 59.62

b = 4000/59.62

b = 67.09

So, now we have both the dimensions a and b

Putting the values of a and b we will get the cost of the construction.

Cost = 180a + 160b

Cost = 180(59.62) + 160(67.09)

Cost = $10,734.4

Hence, $10,734.4 will be the minimum cost of the construction for Bill Ding.    

5 0
3 years ago
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