The rectangle room is 2 times as long as it wide and its perimeter is 30 meters. Find the dimensions of the room.
1 answer:
Answer:
l = 10 m
w = 5 m
Steps:
Set equations:
l = 2w
30 = 2l + 2w
Substitute 2w with l in second equation to find l:
30 = 2l + 2w
30 = 2l + l
10 = l
Plug in 10 into first equation to find w:
l = 2w
10 = 2w
5 = w
You might be interested in
Answer:
The answer is B
Step-by-step explanation:
x/-y is equivalent to -(x/y)
4^(12-4x)=256 realize that 256 is 4^4 so we really have:
4^(12-4x)=4^4 taking the natural log of both sides
(12-4x)ln4=4ln4 dividing both sides by ln4
12-4x=4 subtract 12 from both sides
-4x=-8 divide both sides by -4
x=2
Answer:
56 decreases to 11 because 45 was subtracted from it.
56-45=11
◆ INEQUALITIES ◆
Answer:
3.456
Step-by-step explanation:
one meter is 100 millimeters