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Nataly [62]
4 years ago
14

The rectangle room is 2 times as long as it wide and its perimeter is 30 meters. Find the dimensions of the room.

Mathematics
1 answer:
Pachacha [2.7K]4 years ago
4 0
Answer:
l = 10 m
w = 5 m

Steps:
Set equations:
l = 2w
30 = 2l + 2w

Substitute 2w with l in second equation to find l:
30 = 2l + 2w
30 = 2l + l
10 = l

Plug in 10 into first equation to find w:
l = 2w
10 = 2w
5 = w
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7 0
2 years ago
Help me please don’t need an explanation just a quick answer
Vikki [24]
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5 0
3 years ago
The picture is there​
aliina [53]

Answer:

Step-by-step explanation:

Because CB = 6 cm, we can find CD

Use Triangle CDB.

<BCD = <BCA - <ACD

<BCD = ?

<BCA = 90

<ACD = 60

<BCD = 90 - 60

<BCD = 30

Cos 30 = CD / CB

CD = Cos(30) * BC

CD = 5.196 cm

<A = 90 - ACD

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<A = 90 - 60

<A = 30

Sin(<A) = CB / AB

AB = CB / sin(<A)

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AB = 12

Area =1/2 CD * AB

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