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pychu [463]
3 years ago
12

Write a system of two linear equations in x and y that has the ordered pair solution (4,3).​

Mathematics
2 answers:
natka813 [3]3 years ago
5 0

Answer:

y= x -1

y= 2x-5

Step-by-step explanation:

__________

IceJOKER [234]3 years ago
4 0

Answer:

x + y = 7

x - y = 1

Step-by-step explanation:

4 + 3 = 7

x + y = 7

4 - 3 = 1

x - y = 1

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salantis [7]

Answer:

E.  √180

Step-by-step explanation:

Using Pythagoras' theorem

a^2 + b^2 = c^2 (c = hypotenuse, a and b are legs)

a^2 = c^2 - b^2

a^2 = 18^2 - 12^2

a^2 = 324 - 144

a^2 = 180

a = √180

Answer

E.  √180

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4 years ago
Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re
Yanka [14]

Answer:

Range=14

\sigma^2 =32.4

\sigma = 5 .7

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

Data: 136, 129, 141, 139, 138, 127

Solving (a): The range

This is calculated as:

Range = Highest - Least

Where:

Highest = 141; Least = 127

So:

Range=141-127

Range=14

Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

\bar x = 135

The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

\sigma^2 =\frac{1}{5}*[162]

\sigma^2 =32.4

Solving (c): The standard deviation

This is calculated as:

\sigma = \sqrt {\sigma^2 }

\sigma = \sqrt {32.4}

\sigma = 5 .7 --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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A cylinder has a height of h inches and a diameter of 3 inches.
professor190 [17]

Answer:

Option A

Step-by-step explanation:

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