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3 years ago

8

Ummm... help please? Thanks.

1 answer:

Leni [432]3 years ago

6 0

64 teams began the tournament

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Katie's swim team is having an end-of-season pizza party. When the party started, there was 50 slices of pizza. Now there are 20

kotykmax [81]

Answer:

30alice of pizza they eat

5 0

2 years ago

The length of the base and the height of a triangle are numerically equal. Their sum is 6 less than the number of units in the a

Troyanec [42]

Base = Height, Let them be x.

$( x \times x) \div 2 = (x + x) + 6 \\ x ^{2} \div 2 = 2x + 6 \\ \frac{1}{2} x^{2} - 2x - 6 = 0$
Solve quadratic equation:
x=6, x=-2(rejected because base and height is positive)

6x6/2 =18

6 0

2 years ago

You flip a nickel 100 times and record your results: 35 heads and 65 tails. From your experimental data, what is the probability

musickatia [10]

Out of 100 flips, the nickel landed on tails 65 times.

P(tails)=65/100 or 0.65 or 65%

Answer 65%

4 0

3 years ago

Read 2 more answers

Which statement is true about the extreme value of the given quadratic equation?

ICE Princess25 [194]

Answer:

Option B. The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

$y=-3x^{2}+12x-33$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

$y=-3(x^{2}-4x)-33$

Complete the square

$y=-3(x^{2}-4x+2^2)-33+12$

$y=-3(x^{2}-4x+4)-21$

Rewrite as perfect squares

$y=-3(x-2)^{2}-21$

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

3 0

2 years ago

Solving Quadratic Equations using the Square Root Property

Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

Subtract 10 from both sides.

$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

5 0

3 years ago