2(4x³ + 9m + 3x²)
2(4x³) + 2(9m) + 2(3x²)
8x³ + 18m + 6x²
Answer:
<em>The second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>
Step-by-step explanation:
We can't confirm the length of these diagonals based on the appearance of the figure, so let us apply Pythagorean Theorem;
This diagonal divides each figure ( square + rectangle ) into two congruent, right angle triangles ⇒ from which we may apply Pythagorean Theorem, where the diagonal acts as the hypotenuse;
5^2 + 5^2 = x^2 ⇒ x is the length of the diagonal,
25 + 25 = x^2,
x^2 = 50,
x = √50
Now the same procedure can be applied to this other quadrilateral;
3^2 + 7^2 = x^2 ⇒ x is the length of the diagonal,
9 + 49 = x^2,
x^2 = 58,
x = √58
<em>Therefore the second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>
Answer:
It is s +144=290
Step-by-step explanation:
434 and plese add me as a friend
Answer:
216
Step-by-step explanation:
Plug in 1 to f(x). 2(1) + 4 = 6
Plug that answer in to h(x).
6^3 = 6*6*6 = 216
Answer: 720ways, 24ways
Step-by-step explanation:
Given the seven letter words "SYSTEMS", if E is always occurring before M it means E and M will always be together therefore they letter 'EM' will be taken as an entity to five us 6letters i.e SYST(EM)S.
This can then be arranged in 6!ways
6! = 6×5×4×3×2×1 = 720ways
Similarly, if the E somewhere before the M and the three Ss grouped consecutively, this means E and M must always be together as well as the Ss to give (SSS)YT(EM).
This means that the letters in the bracket can be taken as an entity to give a total of 4 entities. This can them be arranged in 4! ways.
4! = 4×3×2×1
4! = 24ways
