From the identity:
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,
![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)
Answer: b. g(x)=cos^-1(1/x)
First, rearrange the equation so that it is solving for y:
3x - y = 1
+y +y
3x = y + 1
-1 -1
3x - 1 = y
Now substitute the domain values you have listed into the 'x' of the equation to get the values for y.
For example:
3(-3) - 1 = y
-9 - 1 = y
y = -10
I believe the answer is A
3x^-2 can be written
3/x^2 because x^-2 is = 1/x^2
Answer:
About Points
S = (x,y) searched point (it will be in the third quadrant )
M = (-2,0) Midpoint | SP |
P = (3,5) one end of the segment | SP |
You have to draw Cartesian.
we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .
We use the information that | SM | = | MP |
Answer : S = (-7,-5)
Step-by-step explanation:
