Question

Express log2 6 + log2 7 as a single logarithm. A. log2 42 B. log2 √ 42 C. log2 7/6 D. log2 6/7

Answer 1

Answer:

A. $\log _2\left(6\right)+\log _2\left(7\right)=\log _2\left(42\right)$

Step-by-step explanation:

To express $\log _2\left(6\right)+\log _2\left(7\right)$ as a single logarithm you must apply the log rule:

$\log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)$

So,

$\log _2\left(6\right)+\log _2\left(7\right)=\log _2\left(6\cdot \:7\right)$

Multiply the numbers: $6\cdot \:7=42$

$\log _2\left(6\right)+\log _2\left(7\right)=\log _2\left(42\right)$