All categories

3 years ago

Find two consecutive whole numbers that √53 lies between.

Mathematics

1 answer:

4vir4ik [10]3 years ago

4 0

7 is the square root of 49 and 8 is the square toot of 64.
randomly putting stuff i know in

You might be interested in

a baby blue whale weighed 5200 lbs birth. after 2 days the baby weighed 5710. after 14 days the baby weighed 8180 lbs is it prop

sveticcg [70]

Answer:

NOPE

Step-by-step explanation:

6 0

3 years ago

Write an equation for the line described in standard form with x-intercept 4 and y-intercept 5

stealth61 [152]

Answer:

Equation $( \frac{5}{4}) x + y = 5$ is in the standard dorm.

Step-by-step explanation:

Here, the x - intercept = 4 , so ( 4,0) is a point on the line.

and the y - intercept = 5, so ( 0,5) is a point on the line.

So, the slope of the equation is given as = $\frac{y_2 - y_1}{x_2-x_1 } = \frac{5 -0}{0-4} = -\frac{5}{4}$

Now, the SLOPE INTERCEPT FORM of an equation is :

y = mx + b: here m = slope and b = y- intercept

or, $y =-( \frac{5}{4}) x + 5$

Now, standard form is Ax +By = C

So, the standard form is $( \frac{5}{4}) x + y = 5$

Hence, the above equation $( \frac{5}{4}) x + y = 5$

is in the standard dorm.

4 0

2 years ago

I need help with a proof. i only need number 3, 6, & 7. please help!!!

lesya692 [45]

Answer:

boottytff tgggfgv dugddcv

3 0

3 years ago

Which is the solution set of the inequality 15 y minus 9 less-than 36 y greater-than nine-fifths y less-than nine-fifths y less-

Vaselesa [24]

Answer:

C. y<3

Step-by-step explanation:

We are required to determine the solution set of the inequality

$15y-9$

Step 1: Add 9 to both sides

$15y-9+9$

Step 2: Divide both sides by 15

$15y \div 15$

The solution set of the given inequality is: y<3.

The correct option is C.

4 0

3 years ago

Read 2 more answers

Please help me with both questions!!!!

Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0

3 years ago