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2 years ago

8

Devon draws one marble from a bag containing 5 red, 3 green, and 4 yellow marbles. What is the probability that Devon draws a gr

een marble?

1 answer:

goblinko [34]2 years ago

5 0

Answer:

3/12 or 1/4 after simplifying

Step-by-step explanation:

3 chances of getting green because there are 3 green and there is a total of 12 marbles so 3 out of 12, which is equal to one fourth.

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Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB

Digiron [165]

Answer: The distace between midpoints of AP and QB is $\frac{a}{8}$ .

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = $\frac{AP}{2}$

QB = $\frac{AP}{2}$

Substituing:

AP + 2*( $\frac{AP}{2}$ ) = a

2AP = a

AP = $\frac{a}{2}$

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = $\frac{AP}{2}$

QB = $\frac{a}{2}*\frac{1}{2}$

QB = $\frac{a}{4}$

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

$\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}$

$\frac{AP}{2} = \frac{a}{4}$

<u>Midpoint of QB</u>:

$\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}$

$\frac{QB}{2} = \frac{a}{8}$

The distance is:

d = $\frac{a}{4} - \frac{a}{8}$

d = $\frac{a}{8}$

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2 years ago

I need help on this math problem.

olga nikolaevna [1]

(not sure if this is right but)
x (to the 2nd power) + y (to the 2nd power) = cos (90) (to the 2nd power)

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2 years ago

What is the mean, median and mode for a data set of 50,42,55,38,40,55,and 61

nlexa [21]

Mean: 48.7
Median: 38
Mode:55

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3 years ago

.0190500 in scientific notation

arsen [322]

The answer is

1.905×10^-2

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2 years ago

What is the length of the line segment with endpoints (11,−4) and (−12,−4) ?

bija089 [108]

Answer:

Length of the line segment with endpoints (11,−4) and (−12,−4) is 23 units

Step-by-step explanation:

Given:

Endpoints are (11,−4) and (−12,−4)

To Find:

The length of the line = ?

Solution:

The length of the line can be found by using the distance formula

$\sqrt{(x_2-x_1)^2 +(y_2 - y_1)^2$

Here

$x_1$ = 11

$x_2$ = -12

$y_1$ = -4

$y_2$ = -4

Substituting the values

Length of the line

=> $\sqrt{((-12)- 11)^2 +((-4) - (-4))^2$

=> $\sqrt{(-12- 11)^2 +(-4+4)^2$

=> $\sqrt{(-23)^2 +(0)^2$

=> $\sqrt{529}$

=>23

8 0

3 years ago

Read 2 more answers