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mel-nik [20]
4 years ago
12

Fill in what I haven't filled in

Mathematics
1 answer:
Lelu [443]4 years ago
7 0
11/20=.55 =55% ; 1/400=.0025=.25% ; 5/8=.625=62.5%
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if i tossed a coin two times and the results are heads and heads. What is the probability in fraction form?
shutvik [7]

Answer:

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3 years ago
For an arithmetic sequence an = 7+3(n – 1), what is the 31st term?
slamgirl [31]

Answer:

n= 1

Step-by-step explanation:

7+3(n-1)

10(n-1)

10n=10

n=10/10

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3 years ago
-4n+3n is what as an equivalent expression?
Len [333]

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-n

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7 0
3 years ago
The demand function for a product is p=30−3q where p is the price in dollars when q units are demanded. Find the level of produc
Marina86 [1]

Answer: a) Q= 5units

b) R= $75

Step-by-step explanation:

The maximum revenue is at dR/dq = 0

Revenue = price x quantity of demand = p × q

Substituting p = 30- 3q

R = (30-3q) × q

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R= 150- 75

R= $75

Goodluck...

7 0
3 years ago
Read 2 more answers
In the 2000 Sydney Olympics, a special program initiated by IOC president Juan Antonio Samaranch allowed developing countries to
jok3333 [9.3K]

Answer:

The means for times for the first round of the 100 meter men’s swim is 52.64789 seconds

The satandar deviation for times for the first round of the 100 meter men’s swim is 7.60182 seconds

Step-by-step explanation:

The sample mean for a set of n data is given by:

\bar X = \frac{1}{n}\sum{x_i}

In other words, the sample mean of the times for 71 times of the first round measured in seconds is:

\bar X = \frac{1}{71}\sum{x_i} = 52.64789 seconds

The sample standard deviation for a set of n data is given by:

S = \sqrt{\frac{1}{n-1}\sum{(x_i - \bar x)^2}}

In other words, the sample standard deviation of the times for 71 times of the first round measured in seconds is:

S = \sqrt{\frac{1}{n-1}\sum{(x_i - \bar x)^2}} = 7.60182 seconds

8 0
3 years ago
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