<span><span> Let ABC be an isosceles triangle with AB = AC. Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC). Thena)<span> </span>Triangle ABM is congruent to triangle ACM.b)<span> </span>Angle ABC = Angle ACB (base angles are equal)c)<span> </span>Angle AMB = Angle AMC = right angle.d)<span> </span>Angle BAM = angle CAM
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Answer:
Step-by-step explanation:
Let d represent the number of dimes. Then the number of quarters is 2d-3 and the total value of the coins is ...
0.10d + 0.25(2d-3) = 7.05
0.60d -0.75 = 7.05 . . . . . . . simplify
d = (7.05 +0.75)/0.60 = 13 . . . . add 0.75, divide by 0.60
2d-3 = 2·13 -3 = 23
Brandon has 23 quarters and 13 dimes.
Answer:
A
Step-by-step explanation:
really ? you need help to calculate the 2 results of
(2 ± 6) / 2
?
one result is
(2 + 6) / 2 = 8/2 = 4
the other result is
(2 - 6) / 2 = -4/2 = -2
there ! that is all there is to it.
is there still something unclear ?
Answer:
Step-by-step explanation:
<u>Given</u>
- A costs 5$
- B costs $0.25
- C costs $0.05
- A + B + C = 100
- 5A + 0.25B + 0.05C = 100 ⇒ 100A + 5B + C = 2000
<u>Subtract the first equation from the second:</u>
<u>We have a restriction in numbers:</u>
<u>Since 4B can be max 400, we get 99A > 1500 and 99A < 1900 so:</u>
and
A can be 16 or 18 as it should be even number to get B the whole number.
<u>If A = 16:</u>
- 99*16 + 4B = 1900
- 4B = 1900 - 1584
- 4B = 316
- B = 316/4 = 79
<u>If A = 18:</u>
- 99*18 + 4B = 1900
- 4B = 1900 - 1782
- 4B = 118
- B = 118/4 = 29.5, discarded as decimal
<u>So we get:</u>
- A = 16, B = 79 and C = 100 - (16 + 79) = 5
<u>Let's proof the numbers:</u>
- 16*5 + 79*0.25 + 5*0.05 = 100, confirmed
Answer:
254
Step-by-step explanation:
x-39=215
215+39=x
215+39=254
