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iogann1982 [59]
3 years ago
6

The following is a composite figure. Find the TOTAL AREA of

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0
128 inches
for area , you multiply length times height so it’d be 16 x 8 :)
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Which polygon has an interior angle sum of 1260°?
Liono4ka [1.6K]

Answer:

Step-by-step explanation:

Sum of interior angle of any polygon =(n-2) × 180°where n represents the number of sides in any polygon.

Or 1260 =(n-2)x180

Dividing both sides by 180:

7=n-2

Adding both sides by 2 we have :

n=9.

Hence a nanogon will have the sum of interior angles as 1260°.

5 0
3 years ago
Read 2 more answers
E
laiz [17]

Answer:

  44x +56y = 95

Step-by-step explanation:

To write the equation of the perpendicular bisector, we need to know the midpoint and we need to know the differences of the coordinates.

The midpoint is the average of the coordinate values:

  ((-2.5, -2) +(3, 5))/2 = (0.5, 3)/2 = (0.25, 1.5) = (h, k)

The differences of the coordinates are ...

  (3, 5) -(-2.5, -2) = (3 -(-2.5), 5 -(-2)) = (5.5, 7) = (Δx, Δy)

Then the perpendicular bisector equation can be written ...

  Δx(x -h) +Δy(y -k) = 0

  5.5(x -0.25) +7(y -1.5) = 0

  5.5x -1.375 +7y -10.5 = 0

Multiplying by 8 and subtracting the constant, we get ...

  44x +56y = 95 . . . . equation of the perpendicular bisector

8 0
3 years ago
917x2=? yghuyghuyg its so boring, 14 more days of quarantine here :(
Archy [21]
The answer is : 1834
8 0
3 years ago
How much of the sphere do you have to paint red so that no matter ow you put a cube in it, some corner touches red?
Triss [41]

Explanation:

To achive that you have to piant a ring in red, which will have its big diameter equal to the sphere diameter and its small diameter equal to the cube diagonal.

The diagonal of the cube can be calculated using Pithagoras:

D^2=L^2+L^2

Where D is the diagonal and L is the side of the cube

4 0
3 years ago
What are the real zeros of the function g(x)=x^3+2x^2-x-2
Gre4nikov [31]
g(x)=x^3+2x^2-x-2\\\\\text{The zeros:}\\\\g(x)=0\to x^3+2x^2-x-2=0\\\\x^2(x+2)-1(x+2)=0\\\\(x+2)(x^2-1)=0\iff x+2=0\ \vee\ x^2-1=0\\\\x+2=0\ \ \ |-2\\x=-2\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt{1}\to x=-1\ \vee\ x=1\\\\\text{Answer:}\ x=-2\ or\ x=-1\ or\ x=1
4 0
3 years ago
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