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3 years ago

Put these in order from least to greatest 3/10 2/5 and 1/4

Mathematics

2 answers:

LenaWriter [7]3 years ago

6 0

The Answer is...
1/4, 3/10, 2/5

svetoff [14.1K]3 years ago

3 0

2/5 1/4 3/10 that is ur answer 20 percent 25 percent and 30 percent

You might be interested in

How can you use multiplication to help you divide 6000 by 20

SIZIF [17.4K]

6000/20=300

Hope this helps

5 0

2 years ago

Read 2 more answers

Blue

erik [133]

Answer:

30%

Step-by-step explanation:

3+4+6+7= 20

6 (green) / 20

= 30%

6 0

3 years ago

Given F(x)=1/x-4, g(x)=1/6-x. Find f+g(x).

Yakvenalex [24]

$\boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

<h2>Explanation:</h2>

We are given two functions:

$f(x)=\frac{1}{4}x-4 \\ \\ g(x)=\frac{1}{6}-x$

So, we have to find $f(x)+g(x)$ which is the sum of these two functions:

$f(x)+g(x)=\frac{1}{x}-4+\frac{1}{6}-x \\ \\ \\ Let's \ call \ h(x)=f(x)+g(x) \\ \\ Simplifying: \\ \\ h(x)=\left(\frac{1}{x}-x)+(-4+\frac{1}{6}) \\ \\ \\ \\$

$Finally: \\ \\ \boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

<h2>Learn more:</h2>

Shifting graphs: brainly.com/question/10010217

#LearnWithBrainly

3 0

3 years ago

The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3

RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that $p = 0.1$

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243$

There is a 24.3% probability that one of the calculators will be defective.

3 0

4 years ago

Graph the linear equation.<br> x = - 9<br><br><br> help in any way u can please

alukav5142 [94]

This is a vertical line that goes through all points with an x-coordinate of -9.

To graph it, I can give you a couple of points this line goes through so you can draw it more easily.

Points that are on line: (-9,0) and (-9,1)

6 0

3 years ago