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Natalka [10]
3 years ago
14

8xy-3y^2+5x^2-7xy+12x^2-2y^2-3xy+8y^2

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0
 8xy-7xy-3xy-3y²-2y²+8y²+5x²+12x²
then simplify by combining like terms -2xy+3y²+17x²
vfiekz [6]3 years ago
5 0
Can combine like terms
remember yo an move terms around
like terms examples
x and 2x are like
3xy^2 and 4xy^2 are like
x and 2x^2 are not
3x^2y and 3xy are not


group like terms together

I like doing it in power order, highest to lowest

5x²+12x²-3y²-2y²+8y²+8xy-7xy-3xy=
(5x²+12x²)+(-3y²-2y²+8y²)+(8xy-7xy-3xy)=
(17x²)+(-3y²)+(-2xy)=
17x²-3y²-2xy
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Neporo4naja [7]

Answer:

Step-by-step explanation:

8 0
3 years ago
You have 15 dollars and earn 50 more dollars doing chores. You then go to the store to buy a shirt for 10 dollars. How much mone
Sonbull [250]
50 + 15= 65-10= $55 left
4 0
3 years ago
Read 2 more answers
Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot
matrenka [14]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that \overline{AB} \cong \overline{DE} and \overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between \overline{AB} and \overline{DE} in ∆ABC is congruent to the angle between \overline{AC} and \overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be \angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

7 0
3 years ago
A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob
Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012. 
So, the probability that the sample proportion is less than 0.58 
= P(^p<0.58) 
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0... 
= P(z<-0.58) 
= P(z<0) - P(-0.58<z<0) 
= 0.5 - 0.2190 
= 0.281 
<span>So, there is 0.281 or 28.1% probability that the sample proportion is less than 0.58. </span>

4 0
4 years ago
The output is four times the input
juin [17]
O=4i (is that was you were asking about) 

edit: sorry that wasn't very detailed say if the input is 4 the output will be 16 or if the input is 100 the output will be 400. So mainly what ever the input is multiply it by 4.

I hope this helps :)
5 0
3 years ago
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