16 less than one-fourth of some number, w" can be expressed algebraically as

Emily placed her monthly expenses on the budget below to evaluate her excess spending money. Emily's take-home pay is $3,200 eac

Oksana_A [137]

Answer:

Half of the total cost was paid when her braces were put on. The total cost is $3,200. How much will Kelly's parents need to save each month to pay off the ..

Step-by-step explanation:

3 0

3 years ago

Pleassse answer quick! (Again..)

Tema [17]

Well for problems like this you need to look at what is plotted. And you need to look at the y intercept which is the vertical line and the x intercept which is the horizontal line. I think the answer is B because of what is plotted. I am not 100% sure but I think it is. Let me try to look into it more but what is this for? Hw assignment?

3 0

3 years ago

Read 2 more answers

Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 139 to 192 cm and

Bumek [7]

Answer:

The weight of an adult male who is 158 cm tall is 59.32 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

$\hat y=-105+1.04 x$

Here,

y = weight of a person (in kg)

x = height of a person (in cm)

The information provided is:

$\bar x=167.77\ \text{cm}\\\bar y=81.54\ \text{cm}\\r(X, Y)=0.201\\p-value=0.045$

The significance level of the test is, α = 0.01.

The hypothesis to test the significance of the correlation between height and weight is:

H₀: There is no relationship between the height and weight, i.e. ρ = 0.

Hₐ: There is a relationship between the height and weight, i.e. ρ ≠ 0.

Decision rule:

If the p-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

p-value = 0.045 > 0.01

The null hypothesis will not be rejected at 1% level of significance.

Thus, concluding that there is no relationship between the height and weight.

Compute the weight of an adult male with height, x = 158 cm as follows:

$\hat y=-105+1.04 x$

$=-105+(1.04\times 158)\\=-105+164.32\\=59.32$

Thus, the weight of an adult male who is 158 cm tall is 59.32 kg.

6 0

3 years ago

Liz works at a movie theater. Her hourly wage increased from $14.50 to $18 and hour. What was the percent of increase in her hou

melomori [17]

I believe it is 124%

8 0

3 years ago

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Which expression is equivalent to 6–3?

Bond [772]

Your question is not well presented. See complete question below

Which expression is equivalent to $6^{-3}$ ?

A) –63

B) 36

C) $\sqrt[3]{6}$

D) $(\frac{1}{6} )^3$

Answer:

The equivalent of $6^{-3$ is $(\frac{1}{6} )^3$

Step-by-step explanation:

Given

Expression: $6^{-3}$

Required:

Find the Equivalent Expression

To find the equivalent of this expression, we make use of law of indices.

One of the laws of indices states that

$a^-b = \frac{1}{a^b}$

If we apply this law to the expression above ( $6^{-3}$ )

By comparison a = 6 and b = 3.

So, $6^{-3}$ becomes

$6^{-3}$ = $\frac{1}{6^3}$

Simplifying further;

$\frac{1}{6^3}$ = $\frac{1}{6 * 6 * 6}$

This can also be written as

$\frac{1}{6^3}$ = $\frac{1*1*1}{6 * 6 * 6}$

By splitting the above expression; we have that

$\frac{1}{6^3}$ = $\frac{1}{6} * \frac{1}{6} * \frac{1}{6}$

Multiplication law of indices states that;

a * a * a = a³. (Because they have the same base of a)

So, $\frac{1}{6} * \frac{1}{6} * \frac{1}{6}$ can then be written as $(\frac{1}{6} )^3$

Hence, $\frac{1}{6^3}$ = $(\frac{1}{6} )^3$

So, the equivalent of $6^{-3}$ is $(\frac{1}{6} )^3$

7 0

3 years ago

16 less than one-fourth of some​ number, w" can be expressed algebraically as

16 less than one-fourth of some number, w" can be expressed algebraically as