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Leya [2.2K]
3 years ago
11

Need help ASAP! Please

Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

118.5 m

Step-by-step explanation:

I'm not sure what you mean by distance, displacement distance or total distance, so I'm gonna do both.

Displacement =

\int\limits^4_1 {s(t)} \, dt  \\\int\limits^4_1 {5t^2+t+2} \, dt \\\frac{5}{3}(4)^3+\frac{1}{2}(4)^2 + 2(4) - (\frac{5}{3}(1)^3+\frac{1}{2}(1)^2 + 2(1) )\\ = 118.5\\

total distance is just absolute value when using integral

\int\limits^4_1 {| s(t) |} \, dt

= 118.5

luckily it didn't matter for this problem, but there is a significant different between displacement and total distance, so remember to use absolute value signs when needed

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36 fifth graders are on a team with the same number on students on each team, if there are more then then 1 but less then 20 tea
frosja888 [35]

Depending on the number of teams, the possible numbers of students per team are in the set:

{2, 3, 4, 6, 9, 12, 18}

<h3>How many students can be on each team?</h3>

We know that there are 36 students divided equally into N teams.

Such that the number of teams is larger than 1 and smaller than 20.

Then we could have 2 teams, such that the number of students in each team is given by the quotient between the total number of students and the number of teams.

36/2 = 18

There are 18 students in each team.

Notice that the numbers of teams can only be factors of 36, where:

36 = 6*6 = 2*2*3*3

So the factors are:

2, 3, 2*3, 3*3, etc...

If there are 3 teams we have:

36/3 = 12 students per team.

If there are 6 teams we have:

36/6 = 6 students per team.

if there are 9 teams:

36/9 = 4 students per team.

If there are 12 teams:

36/12 = 3 students per team.

If there are 18 teams:

36/18 = 2 students per team.

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If you want to learn more about factors:

brainly.com/question/219464

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7 0
2 years ago
What is the area of the trapezoid?
ExtremeBDS [4]
<h2>Answer:</h2>

42 square units

<h2>Step-by-step explanation:</h2>

For a better understanding, I add an EFGH Rectangle.

The area of EFGH Rectangle = p x l

The area of EFGH Rectangle = 10 x 8

The area of EFGH Rectangle = 80cm²

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x 6 x 4

The area of BHA Triangle = 2 x 6

The area of BHA Triangle = 12cm²

The area of AGD Triangle = 1/2 x a x t

The area of AGD Triangle = 1/2 x 4 x 2

The area of AGD Triangle = 4cm²

The area of CFD Triangle = 1/2 x a x t

The area of CFD Triangle = 1/2 x 2 x 6

The area of CFD Triangle = 6cm²

The area of BEC Triangle = 1/2 x a x t

The area of BEC Triangle = 1/2 x 8 x 4

The area of BEC Triangle = 4 x 4

The area of BEC Triangle = 16cm²

The area of the trapezoid = EFGH Rectangle - (BHA Triangle + AGD Triangle + CFD Triangle + BEC Triangle)

The area of the trapezoid = 80 - (12 + 4 + 6 + 16)

The area of the trapezoid = 80 - 38

The area of the trapezoid = 42cm²

<h3>Conclusion :</h3>

The area of the trapezoid is <u>42 square units</u>

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